Answer:
C. 16√3π in.
Step-by-step explanation:
Circumference of a circle = 2πr where
r is the radius of the circle.
Given the area of one of the smaller circle to be 48π in², we can get the radius of one of the smaller circle.
If A = πr²
48π = πr²
r² = 48
r = √48 in
The radius of one of the smaller circle is √48.
To get the circumference of the larger circle, we need the radius of the larger circle. The radius R of the larger circle will be equivalent to the diameter (2r) of one of the smaller circle.
R = 2r
R = 2√48 inches
Since C = 2πR
C = 2π(2√48)
C = 4√48π in
C = 4(√16×3)π in
C = 4(4√3)π in
C = 16√3π in
Thw circumference of the larger circle is 16√3π in.
Answer:
3x^3 - 11x^2 + 93x - 105
Step-by-step explanation:
(x+5) (x-9) (x+1) (3) FOIL (First, Outside, Inside, Last)...
x^2 - 9x + 5x - 35 (3x+3) Multiply
3x^3 + 3x^2 - 27x^2 - 27x + 15x^2 + 15x - 105x - 105 Combine Like Terms...
3x^3 - 11x^2 + 93x - 105
1) 2.625 miles
2) 5.9 miles
Answer:
N=250
Step-by-step explanation:
"twice as many nickels as dimes" means N =2D [eq1]
"collection of nickels and dimes is worth $25" means
5N + 10D = 2500 [eq2]
(To avoid using decimal points, PLZ express everything in cents.)
Substitution (substitute N from eq1 into eq2]:
5(2D) + 10D = 2500
10D + 10D = 2500
20D = 2500
D = 125
N=2D [eq1 again]
N=2(125)
N=250
Check:
Is 5(250) + 10(125) = 2500 ?
1250 + 1250 = 2500 ?
2500 = 2500 ?yes
