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2 years ago

A group of 8 friends go to the movies. A bag of costs $2.99 how much will it cost to get one bag of popcorn for each friend

Mathematics

1 answer:

Basile [38]2 years ago

5 0

Answer:

$23.92

Step-by-step explanation:

you multiply 2.99 and 8 and get 23.92

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1/6 + 3/8 <br> A. 4/6<br> B. 4/8 <br> C. 4/14<br> D. 13/24

Naddika [18.5K]

Here is you're answer:

In order to get you're answer you need to find the common denominator then add.

$\frac{1}{6} + \frac{3}{8}$
Find the common denominator:
$CD = 48$
$= \frac{26}{48}$
Simplify:
$\frac{26}{48} \div 2 = \frac{13}{24}$
$= \frac{13}{24}$

Therefore you're answer is option D "13/24."

Hope this helps!

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2 years ago

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Answer: First, you identify how many rises and runs the line is from each point on a graph (intersection). Then you take the y's and the x's and do y2-y1/x2-x1 to get the slope!

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2 years ago

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2 years ago

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Please help with this! Jen is deciding to get a new phone. One deal is a free phone with a two year contract, but she will have

Gnom [1K]

All you have to do is add 399 to 10 and then multiply by ten. Then you get 199 and multiply by .08 and multiply that by ten. Then you subtract.

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2 years ago

There were 6 purple socks and 4 oraange socks without looking and then another without looking (or replacing the first). What is

shusha [124]

Answer:

The probability that he picked 2 purpled socks is <u>0.33</u>.

Step-by-step explanation:

Given:

Number of purple socks, $n(P) = 6$

Number of orange socks, $n(O) = 4$

Two socks are picked without replacement.

Now, total number of socks, $n(T)=N(P)+n(O)=6+4=10$

Probability of picking the first cap as purple cap is given as:

$P(P1)=\frac{n(P)}{n(T)}\\\\P(P1)=\frac{6}{10}=\frac{3}{5}$

Since there is no replacement, the number of socks decreases by 1. Also, if the first sock picked is purple, then number of purple socks is also decreased by 1.

Therefore, probability of picking the second cap as purple cap is given as:

$P(P2)=\frac{n(P)-1}{n(T)-1}\\\\P(P2)=\frac{5}{9}$

Now, probability that both the picked caps are purple is given by their probability product. This gives,

$P(P1\ and\ P2)=P(P1)\times P(P2)\\\\P(P1\ and\ P2)=\frac{3}{5}\times\frac{5}{9}\\\\P(P1\ and\ P2)=\frac{3}{9}=\frac{1}{3}=0.33$

Therefore, the probability that he picked 2 purpled socks is 0.33

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2 years ago