Question

PLEASE HELP (25 point!!)

Answer 1

Answer:

#A

G (6,4)

I(3,2)

#B

2^2 + 3^2

4 + 3^2

4 + 9 = 13

13 = C^2

#C

Distance = Square root of (2-4)^2 + (3-6)^2

-2^2 + -3^2

-4 + -9 = -15

Square root of 15 not -15 which is 3.87

Rounded 3.87 = 3.9

Answer 3.9

Answer 2

Answer :Given : points G and I have coordinates (6,4) and (3,2)

To Find : Use  Pythagorean theorem  to calculate the straight line distance between points G and I

Solution:

points G and I have coordinates (6,4) and (3,2)

Draw a line parallel to y axis passing through G

Draw a line parallel to x axis passing through I

Intersection point K ( 6 , 2)

IK = 6 - 3 = 3

GK = 4 -2  = 2

ΔIKG right angled triangle

Pythagoras' theorem: square on the hypotenuse of a right-angled triangle is equal to the sum of the squares of the other two perpendicular sides.  

GI² = IK² + GK²

=>  GI²  = 3² + 2²

=>  GI²  = 13

=> GI = √13

using distance formula

G (6,4) and I (3,2)

= √(6 - 3)² + (4 - 2)²

= √3² + 2²

= √9 + 4

= √13

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