Recall that the area under a curve and above the x axis can be computed by the definite integral. If we have two curves
<span> y = f(x) and y = g(x)</span>
such that
<span> f(x) > g(x)
</span>
then the area between them bounded by the horizontal lines x = a and x = b is
To remember this formula we write
Your answer would be yes, they would be parallel.
We can justify this using co-interior angles, which state that 2 angles subtended by parallel lines add up to 180°
We can check this with both angles 3x & x, or 2x & 90°.
If AD and BC are parallel, then 3x + x = 180, and since you already found the value of x we can substitute this in:
3(45) + (45) = 180
135 + 45 = 180
180 = 180
So the co-interior angles do add up to 180°, which means that AD and BC are parallel.
I hope this helps! Let me know if you have any questions :)
Answer:
3x³ + 13x² + 14x
Step-by-step explanation:
(f × g)(x)
= f(x) × g(x)
= (x + 2)(3x² + 7x)
= x(3x² + 7x) + 2(3x² + 7x) ← distribute parenthesis
= 3x³ + 7x² + 6x² + 14x ← collect like terms
= 3x³ + 13x² + 14x
It’s D because it’s just obvios that there’s not 15% of the kids
The improper fraction is 4 1/3