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Vikentia [17]
3 years ago
11

In a class of 22 students, 13 have a brother and 15 have a sister. There are 3 students who do not have any siblings. What is th

e probability that a student has a brother given that they do not have a sister?
Mathematics
1 answer:
Aneli [31]3 years ago
7 0

Answer:

1/4

Step-by-step explanation:

You might be interested in
Who would you solve 8x+-2y-10
olchik [2.2K]
Okay, for this one I would use elimination:

8x+(-2y)-10
or
8x-2y=10
2x=4y
x=2y
8(2y)-2y=10
16y-2y=10
14y=10
y=5/7
x=10/7 or 1 3/7. Hope it help!
8 0
3 years ago
What is 4n-32? Factor your expression using the greatest common factor.
IgorC [24]

Answer:

4(n-8)

Step-by-step explanation:

take out 4 from 4n-32

so it's 4(n-8) coz 32÷4=8 so yeah

7 0
2 years ago
The table shows information about the masses of some dogs. a) Work out the minimum number of dogs that could have a mass of more
V125BC [204]

Information regarding various dogs' masses is displayed in the table.

(a) 4 bare minimum number of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Given that,

Information regarding various dogs' masses is displayed in the table.

(a)Calculate the bare minimum number of dogs that could weigh more than 27 kg.

(b)Calculate how many dogs, in total, may weigh more than 27 kg.

(a) 4 bare minimum of dogs that could weigh more than 27 kg.

Because the minimum number so lets assume that all dogs in 20≤x<30 are less then 27.

Therefore, 4 bare minimum of dogs that could weigh more than 27 kg.

(b) 17 dogs, in total, may weigh more than 27 kg.

Because the maximum number so lets assume that all dogs in 20≤x<30 are more then 27.

4+13=17

Therefore,17 dogs, in total, may weigh more than 27 kg.

To learn more about numbers visit: brainly.com/question/17429689

#SPJ1

6 0
1 year ago
When bicycles are sold for $200 each, a sports shop can sell 90 bicycles in a season. For every $10 increase
77julia77 [94]
Maybe try add it then takeaway most of it
7 0
3 years ago
A city has a population of 310,000 people. Suppose that each year the population grows by 9%. What will the population be after
Leno4ka [110]

Answer: 644,800

Step-by-step explanation:

This can also be solved using the terms of Arithmetic Progressions.

Let the 13 years be number of terms of the sequences (n)

Therefore ;

T₁₃              = a + ( n - 1 )d , where a = 310,000 and d = 9% of 310,000

9% of 310,000 = 9/100 x 310,000

                        = 27,900

so the common difference (d)

                     d = 27,900

Now substitute for the values  in the formula above and calculate

T₁₃              = 310,000 + ( 13 - 1 ) x 27,900

                  = 310,000 + 12 x 27,900

                  = 310,000 + 334,800

                  = 644,800.

The population after 13 years = 644,800.

 

3 0
3 years ago
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