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dsp73
3 years ago
5

HELP me help help help help

Mathematics
2 answers:
Jet001 [13]3 years ago
6 0

Answer:

(I'll edit this when I get home with the answer)

Step-by-step explanation:

As you see here, draw a line like that, and than each of those 2 triangles have 3 angles that get to 180° in total, so just make an equation of the 3 angles that equals to 180° and than solve for the variable there

Ad libitum [116K]3 years ago
4 0
2x+79+32=180
2x+111=180
2x=69
x=34.5
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Help please!!! I dont understand these questions<br><br><br>currently attaching photos dont delete
Katyanochek1 [597]

Answer:

  1. b/a
  2. 16a²b²
  3. n¹⁰/(16m⁶)
  4. y⁸/x¹⁰
  5. m⁷n³n/m

Step-by-step explanation:

These problems make use of three rules of exponents:

a^ba^c=a^{b+c}\\\\(a^b)^c=a^{bc}\\\\a^{-b}=\dfrac{1}{a^b} \quad\text{or} \quad a^b=\dfrac{1}{a^{-b}}

In general, you can work the problem by using these rules to compute the exponents of each of the variables (or constants), then arrange the expression so all exponents are positive. (The last problem is slightly different.)

__

1. There are no "a" variables in the numerator, and the denominator "a" has a positive exponent (1), so we can leave it alone. The exponent of "b" is the difference of numerator and denominator exponents, according to the above rules.

\dfrac{b^{-2}}{ab^{-3}}=\dfrac{b^{-2-(-3)}}{a}=\dfrac{b}{a}

__

2. 1 to any power is still 1. The outer exponent can be "distributed" to each of the terms inside parentheses, then exponents can be made positive by shifting from denominator to numerator.

\left(\dfrac{1}{4ab}\right)^{-2}=\dfrac{1}{4^{-2}a^{-2}b^{-2}}=16a^2b^2

__

3. One way to work this one is to simplify the inside of the parentheses before applying the outside exponent.

\left(\dfrac{4mn}{m^{-2}n^6}\right)^{-2}=\left(4m^{1-(-2)}n^{1-6}}\right)^{-2}=\left(4m^3n^{-5}}\right)^{-2}\\\\=4^{-2}m^{-6}n^{10}=\dfrac{n^{10}}{16m^6}

__

4. This works the same way the previous problem does.

\left(\dfrac{x^{-4}y}{x^{-9}y^5}\right)^{-2}=\left(x^{-4-(-9)}y^{1-5}\right)^{-2}=\left(x^{5}y^{-4}\right)^{-2}\\\\=x^{-10}y^{8}=\dfrac{y^8}{x^{10}}

__

5. In this problem, you're only asked to eliminate the one negative exponent. That is done by moving the factor to the numerator, changing the sign of the exponent.

\dfrac{m^7n^3}{mn^{-1}}=\dfrac{m^7n^3n}{m}

3 0
3 years ago
The graphs below have the same shape. What is the equation of the blue graph?
Anna11 [10]

Answer:

My best guess will have to be B

Step-by-step explanation:

i remember this question

6 0
3 years ago
-x/6 + 6 = 32<br> What is the answer and how do I solve it
masha68 [24]

Answer:

x= -120

Step-by-step explanation:

-x/6+6+6=32

  1. Use -a/b=a/-b= -a/-b to rewrite the fraction.
  2. -x/-6+6+6=32
  3. Add the two 6's then you get 12
  4. -x/-6+12=32
  5. Multiply both sides with the equation by 6
  6. -x+72=192
  7. Move the constant to the right-hand side and change its side
  8. -x=192+72
  9. Subtract the numbers, -x=192-72
  10. -x=120
  11. Change the signs on both sides of the equation
  12. You have your answer it is x= -120
8 0
3 years ago
B + (4 - a) x 9 = ???
Arte-miy333 [17]

Answer:

-9a + b + 36

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve for x. (X+10)(x+10)=0
atroni [7]

Answer:

use foil method-first inside outside last

Step-by-step explanation:

7 0
3 years ago
Read 3 more answers
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