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dsp73
3 years ago
5

HELP me help help help help

Mathematics
2 answers:
Jet001 [13]3 years ago
6 0

Answer:

(I'll edit this when I get home with the answer)

Step-by-step explanation:

As you see here, draw a line like that, and than each of those 2 triangles have 3 angles that get to 180° in total, so just make an equation of the 3 angles that equals to 180° and than solve for the variable there

Ad libitum [116K]3 years ago
4 0
2x+79+32=180
2x+111=180
2x=69
x=34.5
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Prove that sin3a-cos3a/sina+cosa=2sin2a-1
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Answer:

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

Step-by-step explanation:

we are given

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1

we can simplify left side and make it equal to right side

we can use trig identity

sin(3a)=3sin(a)-4sin^3(a)

cos(3a)=4cos^3(a)-3cos(a)

now, we can plug values

\frac{(3sin(a)-4sin^3(a))-(4cos^3(a)-3cos(a))}{sin(a)+cos(a)}

now, we can simplify

\frac{3sin(a)-4sin^3(a)-4cos^3(a)+3cos(a)}{sin(a)+cos(a)}

\frac{3sin(a)+3cos(a)-4sin^3(a)-4cos^3(a)}{sin(a)+cos(a)}

\frac{3(sin(a)+cos(a))-4(sin^3(a)+cos^3(a))}{sin(a)+cos(a)}

now, we can factor it

\frac{3(sin(a)+cos(a))-4(sin(a)+cos(a))(sin^2(a)+cos^2(a)-sin(a)cos(a)}{sin(a)+cos(a)}

\frac{(sin(a)+cos(a))[3-4(sin^2(a)+cos^2(a)-sin(a)cos(a)]}{sin(a)+cos(a)}

we can use trig identity

sin^2(a)+cos^2(a)=1

\frac{(sin(a)+cos(a))[3-4(1-sin(a)cos(a)]}{sin(a)+cos(a)}

we can cancel terms

=3-4(1-sin(a)cos(a))

now, we can simplify it further

=3-4+4sin(a)cos(a))

=-1+4sin(a)cos(a))

=4sin(a)cos(a)-1

=2\times 2sin(a)cos(a)-1

now, we can use trig identity

2sin(a)cos(a)=sin(2a)

we can replace it

=2sin(2a)-1

so,

\frac{sin(3a)-cos(3a)}{sin(a)+cos(a)} =2sin(2a)-1


7 0
3 years ago
Read 2 more answers
Amal and Salma share some money in the
Oksi-84 [34.3K]
$315, i cant give a thorough explanation since i did it all in my head but basically amal gets 5 portions of the money and Salma gets 9, meaning she gets 4 more, so if 4 portions is $252 then it cant be any of the others since they are too low or way too high, $315 is the only reasonable one.
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3 years ago
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In dealing with surface area, what is a net?
Tju [1.3M]

Answer:

the answer is a.

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Step-by-step explanation:

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Step by step solution :

Step  1  :

Trying to factor as a Difference of Squares :

1.1      Factoring:  x2-2

Theory : A difference of two perfect squares,  A2 - B2  can be factored into  (A+B) • (A-B)

Proof :  (A+B) • (A-B) =

        A2 - AB + BA - B2 =

        A2 - AB + AB - B2 =

        A2 - B2

Note :  AB = BA is the commutative property of multiplication.

Note :  - AB + AB equals zero and is therefore eliminated from the expression.

Check : 2 is not a square !!

Ruling : Binomial can not be factored as the difference of two perfect squares.

Final result :

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Which of the following is a random sample?
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Answer:

A.

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Answer: A.

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