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bixtya [17]
2 years ago
11

A company makes an ice-cream treat in the shape of a hemisphere on top of a cone, as shown below.

Mathematics
1 answer:
lesya [120]2 years ago
6 0

Answer:

56/3 pi  cm^3

Step-by-step explanation:

1/2 volume of sphere = 1/2  4/3 pi r^3

volume of cone   1/3 pi r^2 h

r =2   h = 10  

result :  56/3 pi  cm^3

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in a particular class of 23 students, 18 are men. what fraction of the students in the class are men?k
Mademuasel [1]
It gave you the answer for men they said their were 18 men out of 23 so are they asking for women or actually men cause if it was that it would be 18/23
7 0
3 years ago
Write this trinomial in factored form 2a^2 +7a+3
EleoNora [17]

Answer:

(2a + 1)(a + 3) = 2a² + 7a + 3

8 0
3 years ago
Please help me with this. ​
masya89 [10]

Answer:

a) 48 b) 132 c) 180 d) 228 e) 312

Step-by-step explanation:

3 0
3 years ago
Ten years ago 53% of American families owned stocks or stock funds. Sample data collected by the Investment Company Institute in
Alborosie

Answer:

a) Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

b) z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

p_v =P(Z

c) So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

Step-by-step explanation:

Data given and notation

n=300 represent the random sample taken

\hat p=0.46 estimated proportion of American families owning stocks or stock funds

p_o=0.53 is the value that we want to test

\alpha=0.01 represent the significance level

Confidence=99% or 0.99

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

Concepts and formulas to use  

Part a

We need to conduct a hypothesis in order to test the claim that proportion is less than 0.53 or 53%.:  

Null hypothesis:p\geq 0.53  

Alternative hypothesis:p < 0.53  

Part b

When we conduct a proportion test we need to use the z statistic, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.46 -0.53}{\sqrt{\frac{0.53(1-0.53)}{300}}}=-2.429  

Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.01. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z

Part c  

So the p value obtained was a very low value and using the significance level given \alpha=0.01 we have p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can said that at 1% of significance the proportion of American families owning stocks or stock funds is significantly less than 0.53 .  

7 0
3 years ago
You just drove your car 500 miles and used 20 gallons of gas. You know that the gas tank only holds 18 1/2 gallons of gas. What
sergejj [24]

500 miles / 20 gallons = 25 miles / gallon

25 miles * 18.5 gallons = 462.5 miles / one tank of gas

3 0
3 years ago
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