Answer:
Step-by-step explanation:
Lateral surface area of the triangular prism = Perimeter of the triangular base × Height
By applying Pythagoras theorem in ΔABC,
AC² = AB² + BC²
(34)² = (16)² + BC²
BC = 
= 
= 30 in.
Perimeter of the triangular base = AB + BC + AC
= 16 + 30 + 34
= 80 in
Lateral surface area = 80 × 22
= 1760 in²
Total Surface area = Lateral surface area + 2(Surface area of the triangular base)
Surface area of the triangular base = 
= 
= 240 in²
Total surface area = 1760 + 2(240)
= 1760 + 480
= 2240 in²
Volume = Area of the triangular base × Height
= 240 × 20
= 4800 in³
Answer:
Polygon, quadrilateral, convex, and equilateral.
Step-by-step explanation:
Answer:
<QOS =150°(opp. <'s of a cyclic quard)
<QRS=75°(< at centre =2×< at circumference)
I don't know about the third one bro
Maybe there's an erroron that quation
H(2)=x²=2²=4
G[H(2)]=G(4)=3(4)+2=12+2=14
F[G[H(2)]]=F(14)=2(14)-1=28-1=27
Answer: F[G[H(2)]]=27