Answer:
12-24x
Step-by-step explanation:
This is the concept of algebra, given that ab^4=12 and a^5b^5=7776, the value if a will be found as follows:
ab^4=12
a=12/b^4
also;
a^5=7776/b^5
thus;
a=(7776/b^5)^(1/5)
a=6/b
thus the value of a will be:
6/b=12/b^4
dividing both sides by b we get:
6=12/b^3
multiplying both sides by b^3 we get
6b^3=12
b^3=2
hence;
b=2^(1/3)
Solution: The sample mean of sample 1 is:
![\bar{x}=\frac{4+5+2+4+3}{5}= \frac{18}{5}=3.6](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B4%2B5%2B2%2B4%2B3%7D%7B5%7D%3D%20%5Cfrac%7B18%7D%7B5%7D%3D3.6)
The sample mean of sample 2 is:
![\bar{x}=\frac{2+2+6+5+7}{5}= \frac{22}{5}=4.4](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B2%2B2%2B6%2B5%2B7%7D%7B5%7D%3D%20%5Cfrac%7B22%7D%7B5%7D%3D4.4)
The sample mean of sample 3 is:
![\bar{x}=\frac{4+6+3+4+1}{5}= \frac{18}{5}=3.6](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B4%2B6%2B3%2B4%2B1%7D%7B5%7D%3D%20%5Cfrac%7B18%7D%7B5%7D%3D3.6)
The sample mean of sample 4 is:
![\bar{x}=\frac{5+2+4+3+6}{5}= \frac{20}{5}=4](https://tex.z-dn.net/?f=%5Cbar%7Bx%7D%3D%5Cfrac%7B5%2B2%2B4%2B3%2B6%7D%7B5%7D%3D%20%5Cfrac%7B20%7D%7B5%7D%3D4)
The minimum sample mean of the four sample means is 3.6 and maximum sample mean of the four sample means is 4.4.
Therefore, using his four samples, between 3.6 and 4.4 will Ardem's actual population mean lie.
Hence the option 3.6 and 4.4 is correct
Answer:
Step-by-step explanation:
bsahaahaaana
Answer:
a) θ =
b) r = 31.27 inch
Step-by-step explanation:
(a)
area of sector:
* r² * θ
384 =
* r² * θ
384 =
* (24)² * θ
θ = 384/288
θ = ![\frac{4}{3}\pi](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D%5Cpi)
(b)
384 =
* r² * ![\frac{\pi }{4}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Cpi%20%7D%7B4%7D)
r² = 384 * 2 * ![\frac{4}{\pi }](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B%5Cpi%20%7D)
r² = 977.848
r = √977.848
r = 31.27 inch