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S_A_V [24]
3 years ago
11

Im confused I dont know hoow to reduce

Mathematics
2 answers:
kiruha [24]3 years ago
5 0

Answer:

\frac{5}{6}  -  \frac{1}{6}

\frac{5 - 1}{6}

\frac{4}{6}

\frac{2}{3}

hope this helps you

Rzqust [24]3 years ago
4 0
Answer:

2/3

Step-by-step explanation:

What they mean by reduce is to simplify your answer. Let’s say the answer is 4/10 I can reduce 4/10 by simplifying both sides by 2 = 2/5

Now 5/6 - 1/6 = 4/6 or 2/3

We’re looking for the simplify answer so the answer is 2/3
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Step-by-step explanation:

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2 years ago
Which relation is represented by the arrow diagram?
lorasvet [3.4K]

The relation represented by the arrow diagram is {(-3, 4), (-1, 5), (0, 7), (2, 2), (5, 7)}.

Option: C.

<u>Step-by-step explanation:</u>

A function is a relation in which each input value(domain) results in one output value(range). It is represented diagrammatically using the mapping method.

It shows how each element of domain and range are paired. That is like a flowchart it shows the input values marking its corresponding output value.

In the given diagram,

The values given in the left are domain and values given in the right are range.

Thus, -3 marks to 4, then can be written as (-3,4).

Similarly,

-1 marks 5 = (-1,5).

0 marks 7= (0,7).

2 marks 2= (2,2).

5 marks 7 =(5,7).

⇒ The complete points sequence is {(-3, 4), (-1, 5), (0, 7), (2, 2), (5, 7)}.

7 0
3 years ago
Find a function where f(0)=2 and f(1)=2
xenn [34]

Answer:

Do you want to be extremely boring?

Since the value is 2 at both 0 and 1, why not make it so the value is 2 everywhere else?

f(x) = 2 is a valid solution.

Want something more fun? Why not a parabola? f(x)= ax^2+bx+c.

At this point you have three parameters to play with, and from the fact that f(0)=2 we can already fix one of them, in particular c=2. At this point I would recommend picking an easy value for one of the two, let's say a= 1 (or even a=-1, it will just flip everything upside down) and find out b accordingly:f(1)=2 \rightarrow 1^2+b+2=2 \rightarrow b=-1

Our function becomes

f(x) = x^2-x+2

Notice that it works even by switching sign in the first two terms: f(x) = -x^2+x+2

Want something even more creative? Try playing with a cosine tweaking it's amplitude and frequency so that it's period goes to 1 and it's amplitude gets to 2: f(x) = A cos (kx)

Since cosine is bound between -1 and 1, in order to reach the maximum at 2 we need A= 2, and at that point the first condition is guaranteed; using the second to find k we get 2= 2 cos (k1) = cos k = 1 \rightarrow k = 2\pi

f(x) = 2cos(2\pi x)

Or how about a sine wave that oscillates around 2? with a similar reasoning you get

f(x)= 2+sin(2\pi x)

Sky is the limit.

8 0
2 years ago
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asambeis [7]

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Step-by-step explanation:

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