All categories

3 years ago

Im confused I dont know hoow to reduce

Mathematics

2 answers:

kiruha [24]3 years ago

5 0

Answer:

$\frac{5}{6} - \frac{1}{6}$

$\frac{5 - 1}{6}$

$\frac{4}{6}$

$\frac{2}{3}$

hope this helps you

Rzqust [24]3 years ago

4 0

Answer:

2/3

Step-by-step explanation:

What they mean by reduce is to simplify your answer. Let’s say the answer is 4/10 I can reduce 4/10 by simplifying both sides by 2 = 2/5

Now 5/6 - 1/6 = 4/6 or 2/3

We’re looking for the simplify answer so the answer is 2/3

You might be interested in

PLSSSS HELPP ASSPPPP!!!!

Ne4ueva [31]

The rate of change is 1.5

8 0

3 years ago

Please help if you do not know the answer don’t comment in the answer box just for points

Paul [167]

I don't know all of them but I can tell you that B and E are answers that you should check.

6 0

4 years ago

Read 2 more answers

The radius of the base of a cylinder is decreasing at a rate of 121212 kilometers per second. The height of the cylinder is fixe

WARRIOR [948]

Answer:

7536 $km^3/sec$

Step-by-step explanation:

Given that:

Rate of decreasing of radius = 12 km/sec

Height of cylinder is fixed at = 2.5 km

Radius of cylinder = 40 km

To find:

The rate of change of Volume of the cylinder?

Solution:

First of all, let us have a look at the formula for volume of a cylinder.

$Volume = \pi r^2h$

Where $r$ is the radius and

$h$ is the height of cylinder.

As per question statement:

$r$ = 40 km (variable)

$h$ = 2.5 (constant)

$\dfrac{dV}{dt} = \dfrac{d}{dt}\pi r^2h$

As $\pi, h$ are constant:

$\dfrac{dV}{dt} = \pi h\dfrac{d}{dt} r^2\\\Rightarrow \dfrac{dV}{dt} = \pi h\times 2 r\dfrac{dr}{dt} \\$Putting the values:$\\\Rigghtarrow\dfrac{dV}{dt} = 3.14 \times 2.5\times 2 \times 40\times 12 \\\Rigghtarrow\dfrac{dV}{dt} = 7536\ km^3/sec$

4 0

3 years ago

HELP ASAP!!!!

Alecsey [184]

Answer:

A, C, E, G

Step-by-step explanation:

8 0

3 years ago

Which answer represents the domain of the logarithmic function given below? F(x) = log8x

MrRissso [65]

Answer:

C. $x>0$

Step-by-step explanation:

Given: $f(x)=log(8x)$

To find the domain of a logarithmic function, we need to take the argument, 8x, and set it greater to zero. This is because an argument of a logarithmic function cannot be zero or negative.

$8x>0$

$x>0$

So since x is greater than zero, we have just found out our domain:

Interval Notation: (0, ∞)

Set Notation: { $x|x>0$ }

3 0

3 years ago

Read 2 more answers