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Orlov [11]
3 years ago
6

How many solutions are there to the equation below 6×+30+4×=10(×+3)

Mathematics
1 answer:
Elena-2011 [213]3 years ago
7 0

Answer:

Infinite many solutions. Any x-value can satisfy the equation.

Step-by-step explanation:

Let's work on simplifying the equation a little to investigate which x-values satisfy it. Start by combining like terms on the left side (6x +4x=10x),

then distribute the factor "10" into the binomial (x+10), obtaining 10x +30.

Now we have the same expression on the left and the right of the equal sign:

10x +30=10x+30. We may subtract 30 from both sides, and obtain 10x=10x, and at this point divide by 10 both sides, and we obtain: x=x

The process is shown below.

6x+30+4x=10(x+3)\\6x+4x+30=10x+30\\10x+30=10x+30\\10x=10x\\x=x

x=x is an equation that is verified by absolutely ANY x value on the number line, and there are infinite x-values in the number line.

Therefore there are infinite many solutions to this equation (any x-value will satisfy it).

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Masja [62]

Answer:

6.45

Step-by-step explanation:

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4 0
2 years ago
What are the X and Y intercepts of y= -2(x-4)2 +3
kari74 [83]

Answer: x-intercepts are ( 2.775,0) and (5.225,0)

And y-intercept is (0,-29)

Step-by-step explanation:

Here the given equation is,

y = -2(x-4)^2+3

For x-intercept, y = 0,

Put y = 0 in the above equation of parabola,

We get, -2(x-4)^2 + 3 = 0

-2(x^2+16+8x) + 3 = 0

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By solving this equation,

We get, x = 2.775 or x = 5.225

Therefore, x-intercept of the given parabola are (2.775, 0) and (5.225,0)

Now, for y-intercept, x = 0

By putting x = 0 in the given equation of parabola,

We get, y = -29

Thus, y-intercept of the given parabola = (0,-29)



4 0
3 years ago
The length of a rectangle is 1.2 × 10-4 kilometer. the width of the rectangle is 6.25 × 10-5 kilometer.what is the area in squar
Serhud [2]
We have 1.2 × 10^(-4)  x 6.25 × 10^(-5 )  = 7,5 x 10^(-9) = 75 x 10^(-10) square kilometers.
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3 years ago
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