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2 years ago

11

Micah has 294 songs stored in his phone,which is 70% of the songs that Jorge in his phone.How many songs are stored on Jorge'S p

hone ?

1 answer:

Ipatiy [6.2K]2 years ago

8 0

Answer:

206

Step-by-step explanation:

70% of 294

70/100 × 294/1

205.8

round it off to 206

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A group of people were asked which of three ice cream flavors they prefer. The results are shown in the table.

olchik [2.2K]

Using it's concept, it is found that the probability of a person being over 20 years old and preferring strawberry ice cream is of 12%.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes.</u>

In this problem, there are 8 + 10 + 6 + 8 + 6 + 12 = 50 people, and of those, 6 are over 20 years old and prefer strawberry ice cream, hence the probability is given by:

p = 6/50 = 0.12 = 12%.

More can be learned about probabilities at brainly.com/question/14398287

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1 year ago

A 14.5-gallon gasoline tank is $\frac{3}{4}$

LekaFEV [45]

The answer is in the image. We need 3.625 gallons to fill the tank.

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2 years ago

Select the correct answer.

abruzzese [7]

Solution's

radius =6

Circumference=?

(21π\2)

21* 6/2

=63

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3 years ago

Read 2 more answers

Please look at pic below. Will give 100 points!!!!! NUMBER 2 I NEED HELP

natta225 [31]

Answer:

#2

It is assumed the base of the prism is a square wit side of 5 cm.

<u>The volume is:</u>

V = Bh = 250 cm³

<u>The base is:</u>

B = a² = 5² = 25 cm²

<u>Find h:</u>

h = V/B
h = 250/25 = 10cm

3 0

2 years ago

Read 2 more answers

I know you want to answer this question.

Alik [6]

Answer:

D. x = 3

Step-by-step explanation:

$\frac{1}{2} ^{x-4}$ - 3 = $4^{x-3}$ - 2

First, convert $4^{x-3}$ to base 2:

$4^{x-3}$ = $(2^{2})^{x-3}$

$\frac{1}{2} ^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Next, convert $\frac{1}{2} ^{x-4}$ to base 2:

$\frac{1}{2} ^{x-4}$ = $(2^{-1})^{x-4}$

$(2^{-1})^{x-4}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{-1})^{x-4}$ = $2^{-1*(x-4)}$

$2^{-1*(x-4)}$ - 3 = $(2^{2})^{x-3}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$(2^{2})^{x-3}$ = $2^{2(x-3)}$

$2^{-1*(x-4)}$ - 3 = $2^{2(x-3)}$ - 2

Apply exponent rule: $a^{b+c}$ = $a^{b}$ $a^{c}$ :

$2^{-1(x-4)}$ = $2^{-1x}$ * $2^{4}$ , $2^{2(x-3)}$ = $2^{2x}$ * $2^{-6}$

$2^{-1 * x}$ * $2^{4}$ - 3 = $2^{2x}$ * $2^{-6}$ - 2

Apply exponent rule: $(a^{b})^{c}$ = $a^{bc}$ :

$2^{-1x}$ = $(2^{x})^{-1}$ , $2^{2x}$ = $(2^{x})^{2}$

$(2^{x})^{-1}$ * $2^{4}$ - 3 = $(2^{x})^{2}$ * $2^{-6}$ - 2

Rewrite the equation with $2^{x} = u$ :

$(u)^{-1}$ * $2^{4}$ - 3 = $(u)^{2}$ * $2^{-6}$ - 2

Solve $u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2:

$u^{-1}$ * $2^{4}$ - 3 = $u^{2}$ * $2^{-6}$ - 2

Refine:

$\frac{16}{u}$ - 3 = $\frac{1}{64}$ $u^{2}$ - 2

Add 3 to both sides:

$\frac{16}{u}$ - 3 + 3 = $\frac{1}{64}$ $u^{2}$ - 2 + 3

Simplify:

$\frac{16}{u}$ = $\frac{1}{64}$ $u^{2}$ + 1

Multiply by the Least Common Multiplier (64u):

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify:

$\frac{16}{u}$ * 64u = $\frac{1}{64}$ $u^{2}$ + 1 * 64u

Simplify $\frac{16}{u}$ * 64u:

1024

Simplify $\frac{1}{64}$ $u^{2}$ * 64u:

$u^{3}$

Substitute:

1024 = $u^{3}$ + 64u

Solve for u:

u = 8

Substitute back u = $2^{x}$ :

8 = $2^{x}$

Solve for x:

x = 3

4 0

3 years ago