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nasty-shy [4]
3 years ago
8

Simplify (5x−2+3x^2)+(4x+3)

Mathematics
1 answer:
Art [367]3 years ago
5 0

Answer:

3x^2 + 9x + 1

Or

3x ( x + 3 ) + 1

Step-by-step explanation:

(5x - 2 +3x^2 ) + (4x + 3 )

To make this a little bit more easier to read, you can remove the parentheses:

5x - 2 + 3x^2 + 4x + 3

Now, write in a way so that the like terms are next to each other:

3x^2 + 5x + 4x - 2 + 3

Now simplify the 'x' terms to get:

3x^2 + 9x - 2 + 3

Now, simplify the integers (the ones with now variables with them) to get:

3x^2 + 9x + 1

If you want, you can factor out the 3x for two of the terms to get :

3x ( x + 3 ) + 1

Therefore, your simplest form can either be 3x^2 + 9x + 1 OR 3x (x + 3 ) + 1

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Hey gouys I need help on this to plz help mee
Kaylis [27]

Answer:

d. 3√6 = 7.348

Step-by-step explanation:

1. simplify each expression

a. √150 / 2 = 6.124

b. π + 4 = 7.142

c. 2π = 6.283

d. 3√6 = 7.348

the largest number will be the closest to 8. therefore, point W is expression D.

7 0
3 years ago
Select all of the factors of x3 + 5x2 + 2x – 8.
Nikolay [14]

Answer:

i think it would be multiplied by x

Step-by-step explanation:

that sounds like the best thing to do

5 0
3 years ago
Read 2 more answers
Mandisa draws a rectangle to represent the area of her yard. The area can be represented by 10x2 – 13x – 14.What expressions can
Y_Kistochka [10]

Answer: (x–2) and (10x+7)

Step-by-step explanation:

10x^2 – 13x – 14=

10x^2 – 20x + 7x – 14=

10x(x–2) + 7(x–2)=(x–2)(10x+7) ==> 3rd option

4 0
2 years ago
I need help please.
Ivan

1. It is given that f(x) is 16 times the square root of x.

Putting that in mathematical terms we have,

f(x) = 16 * \sqrt{x}

also, y = f(x)

So, we have the function

y= 16 \sqrt{x}

4. We need to solve the inequality equation : 4x + 2y ≤ 6

Let us take the equation,

4x+2y ≤ 6

2y ≤ 6-4x

y ≤ \frac{6-4x}{2}

y ≤ 3-2x

So, any point (x,y) lies on the given inequality region, where y≤ 3-2x

5. Solving system of equations using addition method

Given:

-5x-y =38          ------> a

-6x-3y =60       -------> b

Divide the equation b by no. 3

(-6x-3y)/3 = 60/3

-2x-y = 20      -------> c

Subtracting equation c from a we have,

-5x-y - (-2x-y) = 38 - 20

-5x-y+2x+y = 18

-3x = 18

x = -6

Now, substituting the value of x in equation a, we get

-5(-6) - y =38

30-y =38

y= 30-38 = -8

y=-8

∴ x = -6 and y = -8

6. Finding composition of functions

Given : f(x) =15x + 7 ; g(x) = x² - 5x

To find : (f+g)(x)

(f+g) (x) = f(g(x))

So, replace the value of x in f(x) by g(x), where g(x)= x² - 5x

(f+g)(x) = 15(x²-5x) +7 =15x²-75x+7

∴ (f + g)(x) = 15x²-75x+7

7. System of 3 equations must be solved to find the solution

-8x-8y-5z=-6

7x-8y-9z =17

9x+2y+6z =-1

Solving by substitution method.

Isolate x from first equation :

x= (-6+8y+5z)/(-8)

Substitute this value of x in 2nd and 3rd equations.

7 (- \frac{-6+8y+5z}{8})-8y -9z = 17

9(- \frac{-6+8y+5z}{8}) + 2y + 6z = -1

Now, isolating y from the 2nd equation rewritten above, we have

y= - \frac{107 z + 94}{120}

Now substituting this value of y in the 3rd equation rewritten above, we have

9(- \frac{-6+8(-\frac{107 z + 94}{120})+5z}{8}) + 2(-\frac{107 z + 94}{120}) + 6z = -1

Isolating z from above equation, we have

z = -2

Substitute z= -2 in the equation of y, we have

y= - \frac{107 (-2) + 94}{120} = 1

y = 1

Substituting the value of y and z, in the equation of x, we have

x= (-6+8(1)+5(-2))/(-8) = 1

x = 1

∴ x=1 ; y = 1 ; z = -2

8. 5x ≤ 7

Solving the above equation, we have

x ≤ 7/5

Please see attachment for the graph.

9. The given function is : g(y) = \sqrt{y} -6

The domain is the set of values of y for which there can be a value of g(y).

Here g(y) can be real only if y is greater than or equal to 0.

∴ The domain of the given function is [0,∞) .

10. Given : y is a function of x.

Definition of function : A function is a relation that associates each element in the domain to one element of another set, the co-domain of the function.

∴ For each element x, in the domain, there is only one value of y in the range.


4 0
3 years ago
If y=5x - 2 were changed to y=3/4 x- 2, how would the graph of the new function compare with the first one?
Andre45 [30]
Hi there! The answer is B. it would be less steep.

The change of the function (in this case) influences the slope of the line. Since we've modified the slope from 5 to 3 / 4, the line will be less steep.
4 0
2 years ago
Read 2 more answers
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