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podryga [215]
3 years ago
5

Un comerciante de régimen código para comprar mercancías gravadas a un comerciante de régimen simplificado precio de venta al pú

blico 1.800.000 incluido el IVA tarifa general (19%)
Computers and Technology
1 answer:
Genrish500 [490]3 years ago
5 0

Answer:

El valor sin impuestos de las mercancías era de $1.512.605.

Explanation:

Dado que un comerciante de régimen código para comprar mercancías gravadas a un comerciante de régimen simplificado pagó un precio de venta al público 1.800.000 incluido el IVA tarifa general (19%), para determinar el valor de las mercancías sin el impuesto incluido se debe realizar el siguiente cálculo:

1.19 = 1.800.000

1 = X

1.800.000 / 1.19 = X

1.512.605 = X

Por lo tanto, el valor sin impuestos de las mercancías era de $1.512.605.

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Create a Card class that represents a playing card. It should have an int instance variable named rank and a char variable named
Helen [10]

Answer:

Explanation:

The following code is written in Java. It creates the Card class and then uses it to create a full house and print out the rank and suit of every card in that hand.

class Card {

   int rank;

   char suit;

   public Card(int rank, char suit) {

       this.rank = rank;

       this.suit = suit;

   }

   public int getRank() {

       return rank;

   }

   public char getSuit() {

       return suit;

   }

}

class CardTester {

   public static void main(String[] args) {

       Card card1 = new Card(3, '♥');

       Card card2 = new Card(3, '♠');

       Card card3 = new Card(3, '♦');

       Card card4 = new Card(2, '♦');

       Card card5 = new Card(2, '♣');

       System.out.println("Card 1: " + card1.getRank() + " of " + card1.getSuit());

       System.out.println("Card 2: " + card2.getRank() + " of " + card2.getSuit());

       System.out.println("Card 3: " + card3.getRank() + " of " + card3.getSuit());

       System.out.println("Card 4: " + card4.getRank() + " of " + card4.getSuit());

       System.out.println("Card 5: " + card5.getRank() + " of " + card5.getSuit());

   }

}

3 0
3 years ago
During her presentation, Marie wanted more freedom to move about the room and interact with her audience. She can use _____.
S_A_V [24]

Answer:

The correct answer is:

"a laser pointer and a remote control"

Explanation:

Let us look at the options one by one.

notes pages and an LCD projector

When she is using these options, she cannot have the freedom to move as she has to operate the projector somehow.

laptop computer and a pointer

In this case she has to operate laptop so movement will be reduced.

<u>A laser pointer and remote control</u> will give her a lot of freedom to move as she can use the remote control to operate the slides and the pointer to point stuff ont the slides.

Hence,

The correct answer is:

"a laser pointer and a remote control"

5 0
3 years ago
tiny electrical paths to connect everything together is called ? A. graphic card B. audio card C. CPU D. Motherboard
k0ka [10]

Answer:

Option C, or the CPU.

Explanation:

The audio card simply translate code into sound, the graphic card turns code into graphics, CPU runs electric through tons of little electric pathways, and the motherboard is the object of which all of the above are rested on and connects them together.

8 0
3 years ago
Write a loop that subtracts 1 from each element in lowerScores. If the element was already 0 or negative, assign 0 to the elemen
Verdich [7]

Answer:

Replace <STUDENT CODE> with

for (i = 0; i < SCORES_SIZE; ++i) {

       if(lowerScores.at(i)<=0){

           lowerScores.at(i) = 0;

       }

       else{

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Explanation:

To do this, we simply iterate through the vector.

For each item in the vector, we run a check if it is less than 1 (i.e. 0 or negative).

If yes, the vector item is set to 0

If otherwise, 1 is subtracted from that vector item

This line iterates through the vector

for (i = 0; i < SCORES_SIZE; ++i) {

This checks if vector item is less than 1

       if(lowerScores.at(i)<1){

If yes, the vector item is set to 0

           lowerScores.at(i) = 0;

       }

       else{

If otherwise, 1 is subtracted from the vector item

           lowerScores.at(i) = lowerScores.at(i) - 1;

       }  

   }

Also, include the following at the beginning of the program:

<em>#include <vector></em>

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