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adoni [48]
3 years ago
7

Math 8: Linear Functions, Part 2

Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

\boxed{\text{1. y + 5 = -4(x - 3); \qquad 2. y - 8 = x + 1}}

Step-by-step explanation:

Question 1

The point-slope formula for a straight line is

y – y₁ = m(x – x₁)

x₁ = 3; y₁ = -5; m = -4  

Substitute the values

\boxed{\textbf{y + 5 = -4(x - 3)}}

The diagram shows the graph of equation 1 (red) with slope -4 passing through (3,-5).

Question 2

x₁ = -1; y₁ = 8; m = 1  

Substitute the values

\boxed{\textbf{y - 8 = x + 1}}

The diagram shows the graph of equation 2 (green) with slope 1 passing through (-1,8).

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Answer:

  • The general equation of the circle is
  • ( {x - a})^{2}  +  ({y - b})^{2}  =  {r}^{2}  \\ therefore \:  we \: \: have \:  \\ ( {x - 2})^{2}  + (y - ( - 5)) {}^{2}  =  ({16})^{2}  \\  ({x - 2})^{2}  + ( {y + 5})^{2}  = 256
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Step-by-step explanation:

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I need help with this
yanalaym [24]

The answer is the "y" value of (2, 3),


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Help Anyone please? >>>>>>>>>>>>>>>>>>>>>>>>>>>
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