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adoni [48]
3 years ago
7

Math 8: Linear Functions, Part 2

Mathematics
1 answer:
Studentka2010 [4]3 years ago
3 0

Answer:

\boxed{\text{1. y + 5 = -4(x - 3); \qquad 2. y - 8 = x + 1}}

Step-by-step explanation:

Question 1

The point-slope formula for a straight line is

y – y₁ = m(x – x₁)

x₁ = 3; y₁ = -5; m = -4  

Substitute the values

\boxed{\textbf{y + 5 = -4(x - 3)}}

The diagram shows the graph of equation 1 (red) with slope -4 passing through (3,-5).

Question 2

x₁ = -1; y₁ = 8; m = 1  

Substitute the values

\boxed{\textbf{y - 8 = x + 1}}

The diagram shows the graph of equation 2 (green) with slope 1 passing through (-1,8).

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