The answer is (base×height)÷2
Answer:
The motorist's average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.
Step-by-step explanation:
Let the motorist's average rate in the afternoon = <em>x</em> mph.
It is given that his average rate in the morning was twice his average rate in the afternoon.
Therefore, his average rate in the morning = 2<em>x</em> mph.
Let <em>t</em> be the time taken for the morning trip.
It is given that he spent 5 hours for driving.
So, the time taken by him for the afternoon trip = 5 - <em>t</em>.
Now, using the formumla, ,
the verbal model for the morning trip is:
<em>xt</em> = 75
The verbal model for the afternoon trip is:
5<em>x</em> - <em>xt</em> = 50
Substituting <em>xt</em> = 75, we get,
5<em>x</em> - 75 = 50
5<em>x</em> = 125
<em>x</em> = 25
2<em>x</em> = 50
Hence, his average rate in the morning trip was 50 mph and that for the afternoon trip was 25 mph.
You mix the letters A, C, Q, U, A, I, N, T, A, N, C, and E thoroughly. Without looking, you select one letter. Find P(Q or C) as
Zina [86]
Answer:
P(Q or C) = 0.25
Step-by-step explanation:
We are given the following in the question:
Letters:
A, C, Q, U, A, I, N, T, A, N, C, E
Total number of observations, n = 12
We have to find the probability that a randomly selected letter is Q or C.
Formula:
P(Q or C) =
Thus,
P(Q or C) = 0.25