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3 years ago

Can you please write the equation and answer for the following question;

Mathematics

1 answer:

Charra [1.4K]3 years ago

3 0

44 is your anwser
hope you do great !!!!!!!!!!

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Can y'all please solve this.....will give brainliest ^_^

Jlenok [28]

Answer: a) 1.1962

after sig figs it’s 1.2

b) 0.4321

after sig figs it’s 0.43

Step-by-step explanation:

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2 years ago

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Fred and Victoria provide the following proofs for vertical angles to be equal:

mart [117]

Answer should be <span>Both Fred's and Victoria's proofs are correct.</span>

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3 years ago

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I need help on the yes and no one

lutik1710 [3]

Hello from MrBillDoesMath!

Answer:

10a. YES

10b. YES

10c. NO

10d . YES

Discussion:

If x = 12

10a. Does (3/4) 12 = 9? Does (36/4) = 9 = 9? YES

10b. Does 3x = 36? Does 3(12) = 36 = 36? YES

10c. Does 5x = 70? Does 5(12) = 60 = 70? NO

10d. Does x/3 = 4? Does 12/3 = 4 = 4 ? YES

Thank you,

MrB

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3 years ago

plain why the function is discontinuous at the given number a. (Select all that apply.) f(x) = x2 − 2x x2 − 4 if x ≠ 2 1 if x =

ElenaW [278]

Answer with Step-by-step explanation:

We are given that

$f(x)=\left\{\begin{matrix}\dfrac{x^2-2x}{x^2-4}&,if\ \ x\neq 2 \\ 1&,if\ \ x=2\end{matrix}\right.$

We have to explain that why the function is discontinuous at x=2

We know that if function is continuous at x=a then LHL=RHL=f(a).

$f(x)=\frac{x(x-2)}{(x+2)(x-2)}=\frac{x}{x+2}$

LHL=Left hand limit when x <2

Substitute x=2-h

where h is small positive value >0

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2-h}{2-h+2}$

$\lim_{h\rightarrow 0}\frac{2-h}{4-h}=\frac{2}{4}=\frac{1}{2}$

Right hand limit =RHL when x> 2

Substitute

x=2+h

$\lim_{h\rightarrow 0}f(x)=\lim_{h\rightarrow 0}\frac{2+h}{2+h+2}=\lim_{h\rightarrow 0}\frac{2+h}{4+h}$

$=\frac{2}{4}=\frac{1}{2}$

LHL=RHL= $\frac{1}{2}$

f(2)=1

$LHL=RHL\neq f(2)$

Hence, function is discontinuous at x=2

4 0

3 years ago

If JKL ~ MKN, find the value of x.

ella [17]

Answer: X=14

Step-by-step explanation:

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3 years ago