Explanation:
#37: The data is per milliliter, so to find out how much pen*cillin is present for TEN milliliters, multiply the value by 10. So, after 5 minutes, there were 152 micr*grams of penic*llin per milliliter in the kidn*ys, which means 1520 (152 x 10) micr*grams per TEN milliliters of bl*od. Now, for step 2 we need to go to row three and calculate the amount of penic*llin (in micr*grams, no conversion necessary) per EIGHT milliliters of bl*od, NOT TEN. Therefore, we are going to multiply the per milliliter value by EIGHT. 118 x 8 = 944. To answer the question we need to find the positive difference (the questions asks for how much MORE, NOT LESS) between 1520 and 944. This is 576 (1520 - 944 = 576).
#38: to get an the most accurate reading for variable P, you can use any data in the table except for row one, because this is immediately after injection, the full amount of penic*llin given in the d*se.
Formula for depreciation of penic*llin in body after inj*ction (measured in intervals of 5 mintues): P(t) = 200b^(t/5)
See, if we solve for "b" using any of the rows after 1 we will get a very similar answer and when rounded to the nearest tenth, they will all equal 0.8.
**the "P(t)" is the same as function of x which is equivalent to the output (y value) in a table.
<h2>Row Two</h2>
(nearest tenth)
<h2>Row Three</h2>
(nearest tenth)
<h2>Row Four</h2>
![P(15) = 200b^(15/5)\\93 = 200b^3\\93/200 = b^3\\0.465 = b^3\\b = \sqrt[3]{0.465} = 0.774731089\\b = 0.77 = 0.8](https://tex.z-dn.net/?f=P%2815%29%20%3D%20200b%5E%2815%2F5%29%5C%5C93%20%3D%20200b%5E3%5C%5C93%2F200%20%3D%20b%5E3%5C%5C0.465%20%3D%20b%5E3%5C%5Cb%20%3D%20%5Csqrt%5B3%5D%7B0.465%7D%20%3D%200.774731089%5C%5Cb%20%3D%200.77%20%3D%200.8)
(nearest tenth)
<h2>Row Five</h2>
![P(20) = 200b^(20/5)\\74 = 200b^4\\74/200 = b^4\\37/100 = b^4\\b^4 = .37\\b = \sqrt[4]{0.37} = 0.77992067098508\\b = 0.78 = 0.8](https://tex.z-dn.net/?f=P%2820%29%20%3D%20200b%5E%2820%2F5%29%5C%5C74%20%3D%20200b%5E4%5C%5C74%2F200%20%3D%20b%5E4%5C%5C37%2F100%20%3D%20b%5E4%5C%5Cb%5E4%20%3D%20.37%5C%5Cb%20%3D%20%5Csqrt%5B4%5D%7B0.37%7D%20%3D%200.77992067098508%5C%5Cb%20%3D%200.78%20%3D%200.8)
(nearest tenth)
Answer:
Explanation:
1. ਕੋਈ ਵਿਅਕਤੀ ਜੋ ਕਿਸੇ ਧਾਰਮਿਕ ਜਾਂ ਰਾਜਨੀਤਕ ਵਿਸ਼ਵਾਸ ਜਾਂ ਸਿਧਾਂਤ ਨੂੰ ਤਿਆਗਦਾ ਹੈ
2. ਇੱਕ ਨੂੰ ਦਿੱਤਾ ਗਿਆ
3. ਨਾਲ ਦੇ ਜਾਂ ਨਜ਼ਦੀਕੀ ਸ਼ਬਦਾਂ ਦੇ ਸ਼ੁਰੂ ਵਿੱਚ ਇੱਕੋ ਅੱਖਰ ਜਾਂ ਧੁਨੀ ਦੀ ਘਟਨਾ।
4. ਕੋਈ ਵਿਅਕਤੀ ਜੋ ਪਰਮੇਸ਼ੁਰ ਜਾਂ ਦੇਵਤਿਆਂ ਦੀ ਹੋਂਦ ਵਿੱਚ ਵਿਸ਼ਵਾਸ ਼ ਨਹੀਂ ਕਰਦਾ ਜਾਂ ਉਸਵਿੱਚ ਵਿਸ਼ਵਾਸ ਨਹੀਂ ਰੱਖਦਾ
5. ਇੱਕ ਰਵਾਇਤੀ ਕਹਾਣੀ ਜਿਸਨੂੰ ਕਈ ਵਾਰ ਇਤਿਹਾਸਕ ਪਰ ਪ੍ਰਮਾਣਿਤ ਨਹੀਂ ਮੰਨਿਆ ਜਾਂਦਾ
hope it helps
The statements that represent a Theory X manager's beliefs are:
- Workers are motivated by fear and money.
- Workers prefer to avoid responsibility.
<h3>What is McGregor's theory of X and Y?</h3>
In 1960, a man known as Douglas McGregor was known to have created or postulated the Theory X and Theory Y and this is one that states that two areas of human behavior at work,
Note that it tells about the two different views of people (employees): one that is negative, called the Theory X and the other is known to be positive, and it is called Theory Y.
Hence when liked to the above, The statements that represent a Theory X manager's beliefs are:
- Workers are motivated by fear and money.
- Workers prefer to avoid responsibility.
Learn more about McGregor's Theory From
brainly.com/question/12440324
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Answer:
X = 4.50
Explanation:
Hope this helps. If it did, please mark as brainliest. Thanks.
What the sample suggests is that; the mean body temperature couldvery possibly bevery possibly be 98.6 °F.
<h3>What is the Confidence Interval?</h3>
For a 99% Confidence Interval and DF = 103 - 1 = 102, the value of z = 2.33.
The formula for confidence interval is;
CI = x⁻ ± z(σ/√n))
We are given;
Sample mean; x⁻ = 98.9
standard deviation; σ = 0.67
sample size; n = 103
Thus the confidence Interval is;
CI = [98.9 - 2.33(0.67/√103)], [98.9 + 2.33(0.67/√103)]
CI = (98.9 - 0.154, 98.5 + 0.154)
CI = (98.36, 98.64)
Thus, 98.6 is contained within the 99% CI,and so we can conclude that the the mean body temperature could very possibly bevery possibly be 98.6 °F.
Read more about Confidence Interval at; brainly.com/question/17097944
