(1/2)^3-(1/4)^2+1/2 help?

Mathematics

1 answer:

mrs_skeptik [129]3 years ago

5 0

Answer:

$(\frac{1}{2}) ^{3} - (\frac{1}{4} )^{2} +\frac{1}{2} = \frac{9}{16}$

Step-by-step explanation:

Explanation:-

Given

$(\frac{1}{2}) ^{3} - (\frac{1}{4} )^{2} +\frac{1}{2}$

= $\frac{1}{8} - \frac{1}{16} + \frac{1}{2}$

$=\frac{2-1}{16} + \frac{1}{2}$

= $\frac{1}{16} + \frac{1}{2}$

= $\frac{1+8}{16}$

= $\frac{9}{16}$

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<h3>Evaluating expressions:</h3>

Evaluating an expression just means that we need to replace the variable in the expression for a given value, here we have the expression:

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