When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now first write the balanced chemical equation
CuSO₄ (aq) + Na₂S (aq) → CuS(s) + Na₂SO₄ (aq)
Now write the net ionic equation
Cu⁺² (aq) + SO₄⁻² (aq) + 2Na⁺ (aq) + S⁻² (aq) → CuS (s) + 2Na⁺ + SO₄⁻² (aq)
So the net ionic equation is
Cu⁺² (aq) + S⁻² (aq) → CuS (s)
Thus from the above conclusion we can say that When solutions of sodium sulfide and copper(ii) sulfate are mixed, a precipitate of copper(ii) sulfide is formed. The net ionic equation for this reaction is Cu⁺² (aq) + S⁻² (aq) → CuS (s).
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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Answer:
C.Energy is absorbed because the products have more chemical energy than the reactants.
Explanation:
Answer:
1.6 × 10²³ molecules of N2O5
Explanation:
To find the amount of molecules from the amount of moles of a substance we simply multiply the amount of moles by Avagadro's number.
0.27mol × 6.02×10²³ = 1.6 × 10²³ molecules of N2O5
Heat energy released : 167.2 kJ
<h3>Further explanation</h3>
Heat can be calculated using the formula:
Q = mc∆T
Q = heat, J
m = mass, g
c = specific heat, joules / g ° C
∆T = temperature difference, ° C / K
m = 2000 g
c = 4.18 J/ g ° C
∆t = 20 ° C
Answer: -
405 mL
Explanation: -
Initial Pressure P 1 = 0.6 atm
Final Pressure P 2 = 0.2 atm
Initial volume V 1 = 135 mL
Using Boyle's Law,
At constant temperature,
P 1 x V 1 = P 2 x V 2
0.6 atm x 135 mL = 0.2 atm x V 2
Final volume = V 2 = 
= 405 mL
Thus if a sample of gas has a volume of 135 ml at 0.600 atm. 405 mL would be the volume if the pressure is decreased to 0.200 atm while temperature is held constant.
