Answer:
Explanation:
Hello!
In this case, since the density is defined as the degree of compactness of a substance, and is defined as the mass over the volume:
Given the dimensions of the bar of lead, we can compute the volume as shown below:
Thus, the density turns out:
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The answer is 1.6 atm. Let's first calculate the mole fraction of gas Y.
The mole fraction (x) is: x = n1/n, where n1 is a number of moles of an
individual gas in a mixture and n is total moles of the gas mixture. We
know that n1 of gas Y is 6.0 mol (n1 = 6.0 mol) and that there are in
total 8. mol of the gas mixture (n = 2.0 + 6.0 = 8.0 mol). Now calculate
the mole fraction of gas Y. x = 6.0/8.0 = 0.75. Now, let's use the mole
fraction of gas Y (x) and the total pressure (P) to calculate the
partial pressure of gas Y (P1): x = P1/P. P1 = x * P. If x = 0.75 and P =
2.1 atm, then the partial pressure of gas Y is: P1 = 0.75 * 2.1 atm =
1.6 atm.
Answer:
0.3477 grams
The conversion factor is 1/1000
Explanation:
347.7 mg = 0.3477 grams
1 mg = 1x10⁻³ g
1 g / 1000 mg . 347.7 mg = 0.3477 grams
