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lisabon 2012 [21]
3 years ago
7

How do you calculate molar mass?

Chemistry
1 answer:
WARRIOR [948]3 years ago
7 0
Look at the periodic table and determine the atomic weight of each element. Multiply each atomic weight by the number of atoms in the formula. Then add up the results together to get your answer.  
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One mole of a metallic oxide reacts with one mole of hydrogen to produce two moles of the pure metal
Rudiy27

Answer:

Lithium oxide, Li₂O.

Explanation:

Hello!

In this case, according to the given amounts, it is possible to write down the chemical reaction as shown below:

M_2O+H_2 \rightarrow 2M+H_2O

Which means that the metallic oxide has the following formula: M₂O. Next, we can set up the following proportional factors according to the chemical reaction:

5.00gM_2O*\frac{1molM_2O}{(2x+16)gM_2O}*\frac{2molM}{1molM_2O}*\frac{xgM}{1molM}   = 2.32gM

Thus, we perform the operations in order to obtain:

\frac{10x}{2x+16}=2.32

So we solve for x as shown below:

10x = 2.32(2x+16)\\\\10x = 4.64x+37.12\\\\x = \frac{37.12}{10-4.64}\\\\x= 6.93 g/mol

Whose molar mass corresponds to lithium, and therefore, the metallic oxide is lithium oxide, Li₂O.

Best regards!

8 0
3 years ago
An element has an atomic number of 92 and a mass number of 234, how many neutrons are there?
Sergio039 [100]
Mass number minus atomic number equals neutrons.
234-92=142
8 0
3 years ago
Point G is the center of the small circle. Point X is the
Dafna1 [17]

Answer:

C

Explanation:

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4 0
3 years ago
A common radio wavelength observed coming from astronomical objects is 21 cm. What temperature is associated with this radiation
qaws [65]

Answer:

The temperature associated with this radiation is 0.014K.

Explanation:

If we assume that the astronomical object behaves as a black body, the relation between its <em>wavelength</em> and <em>temperature</em> is given by Wien's displacement law.

\lambda_{max}=\frac{b}{T}

where,

λmax is the wavelength at the peak of emission

b is Wien's displacement constant (2.89×10⁻³ m⋅K)

T is the absolute temperature

For a wavelength of 21 cm,

T=\frac{b}{\lambda _{max} } = \frac{2.89 \times 10^{-3} m.K  }{0.21m} =0.014K

8 0
3 years ago
What was Thompson’s model of the atom called
shtirl [24]

J. J. Thomson, who discovered the electron in 1897, proposed the plum pudding model of the atom in 1904 before the discovery of the atomic nucleus in order to include the electron in the atomic model. In Thomson's model, the atom is composed of electrons (which Thomson still called “corpuscles,” though G. J.

4 0
3 years ago
Read 2 more answers
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