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Oksi-84 [34.3K]
3 years ago
8

How much interest will be earned on a $2000 investment at 8.29% compounded

Mathematics
1 answer:
valentinak56 [21]3 years ago
6 0

Answer:The final balance is $3,272.2.

The total compound interest is $1,272.2.

Step-by-step explanation:

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The first term of an arithmetic sequence is 4. The
Sliva [168]
-1 i think that the answer is -1
5 0
3 years ago
Simplify. (3x^2 + 3) - (6x + 4) + (3x^2 - 5x)
r-ruslan [8.4K]

Answer:

6x^2 -11x -1

Step-by-step explanation:

(3x^2 + 3) - (6x + 4) + (3x^2 - 5x)

Distribute the minus sign

(3x^2 + 3) - 6x - 4) + (3x^2 - 5x)

Combine like terms

3x^2 + 3x^2 - 6x  - 5x -4+3

6x^2 -11x -1

3 0
3 years ago
The first inverse operation you would use to solve the equation 2+5x= -8 for x is subtraction. true or false?
jok3333 [9.3K]

Answer:

It would be True

Step-by-step explanation:

2+5x = -8

SUBTACT 2 on both sides and it would look like this:

5x = -8 - (2)

5X= -10

then DIVIDE 5 both side to get "X" ALONE,

x= -10/5

then divide -10 with 5

equal to:

x = -2

4 0
3 years ago
Can anyone help me on this please
vazorg [7]

Answer:

201.06

Step-by-step explanation:

hope this helps!!!!

3 0
3 years ago
Someone help with this
elena-14-01-66 [18.8K]

The quadrants are I, II, III, and IV, (meaning 1, 2, 3, and 4). The first quadrant is in the upper right, which has both positive x and positive y values. The second quadrant is the upper left, which has negative x and positive y values. The third quadrant is the lower left, which has both negative x and y values. The fourth quadrant is the lower right, which has positive x and negative y values. Using this knowledge and our positive and negative signs, the following are the answers to questions 1-6.

1) (-4, -2) - Quadrant III, both x and y are negative

2) (0, -7) - This point is actually on the y-axis. The x value is 0 and the y value is -7, so the graph is 7 units down from the origin on the y-axis.

3) (0,0) - This point is the origin, or where the x and y axes cross (the middle of the graph).

4) (6, -9) - This point is in Quadrant IV, because it has a positive x value and a negative y value

5) (3,5) - This point is in Quadrant I, because both the x and y values are positive.

6) (8,0) - This point is on the x-axis. The y-value is zero, so this point is 8 units to the right of the origin between Quadrant I and Quadrant IV.

Using the knowledge presented above, to graph the points given to you in the second part of the problem, first you can figure out what quadrant or part of the graph the point is on. Then, you can count the number of units (squares on the graph) in the right direction (remember that up is positive on the y-axis and down is negative, and to the right is positive on the x-axis and to the left is negative) in order to plot the points. Then, you must connect the points that correspond to the same figure in order to create the figures.

Please comment if you have any questions!

Hope this helps!

7 0
4 years ago
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