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Margaret [11]
3 years ago
8

Is (-6,7) a solution to this system of inequalities? Y> -x + 1 Y > 1/3x -9

Mathematics
2 answers:
Firlakuza [10]3 years ago
4 0
I got 6 and -7 when I did this problem, maybe you made a mistake or maybe I did. But you are on the right track
svet-max [94.6K]3 years ago
4 0

Answer:

y>-x+1

7>-x(6)+1

7>6x+1

6>6x

1>x

y>1/3x-9

7>1/3x(-6)-9

7>-2x-9

16>-2x

8>x

Both of these equations are true which means this coordinate point is a solution to this set of equations.

Hope this helps!  :)

Step-by-step explanation:

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\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\ 1.AY=BX&\text{1. Given}\\ 2.AB \cong AB&\text{2. Reflexive Property}\\ 3. AD || BC&\text{3. Property of a square}\\ 4. \angle ABE \cong \angle AXB&\text{4. Alternate Interior Angles}\\ 5. \angle BAY \cong \angle BYA&\text{5. Alternate Interior Angles}\\6. \triangle BAX \cong \triangle ABY&\text{6. Angle-Side-Angle Theorem}\\ 7. AX \cong BY&\text{7. CPCTC}\\\end{array}

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\begin{array}{c|c}\underline{Statement}&\underline{Reason}\\1. AB=CF&\text{1. Given}\\2.AB+BF=A'F&\text{2. Segment Addition Postulate}\\3.CF+BF=A'F&\text{3. Substitution Property}\\4.CF+BF+BC&\text{4. Segment Addition Postulate}\\5.A'F=BC&\text{5. Transitive Property}\\6. \angle AFE = \angle DBC&\text{6. Given}\\7. EF = BD&\text{7. Given}\\8. \triangle AFE \cong \triangle CBD&\text{8. Side-Angle-Side Theorem}\\\end{array}

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