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3 years ago

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the tempature dropped 8 degrees between 6:00 p.m. and midnight. The tempature at midnight was 26 degreesF. Write and solve an eq

uation to find the tempature at 6:00 p.m.

2 answers:

mr Goodwill [35]3 years ago

8 0

Since it dropped 8 degrees, we actually need to add. So, just do 26+8 which is 34. The temperature at 6:00 PM was 34 degrees. I hope this helped!

sashaice [31]3 years ago

3 0

D=degrees at 6

26-8=d
d=18

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Ray Of Light [21]

First, find the simplified ratio of the given ratio:

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Divide 22 with 2 to find the ratio: 22/2 = 11

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Now, find the ratio for the other questions:

IF there are 5 ships: 5 x 11 = 55

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2 years ago

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Solve the problem. Use the Central Limit Theorem.The annual precipitation amounts in a certain mountain range are normally distr

bazaltina [42]

Answer:

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

Step-by-step explanation:

To solve this question, we use the normal probability distribution and the central limit theorem.

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem establishes that, for a normally distributed random variable X, with mean $\mu$ and standard deviation $\sigma$ , the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$ .

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Mean of 109.0 inches, and a standard deviation of 12 inches.

This means that $\mu = 109, \sigma = 12$

Sample of 25.

This means that $n = 25, s = \frac{12}{\sqrt{25}} = 2.4$

What is the probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches?

This is the p-value of Z when X = 112. So

$Z = \frac{X - \mu}{\sigma}$

By the Central Limit Theorem

$Z = \frac{X - \mu}{s}$

$Z = \frac{112 - 109}{2.4}$

$Z = 1.25$

$Z = 1.25$ has a p-value of 0.8944.

0.8944 = 89.44% probability that the mean annual precipitation during 25 randomly picked years will be less than 112 inches.

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3 years ago

Number of passengers who arrive at the platform in an amtrack train station for the 2 pm train on a saturday is a random variabl

alexgriva [62]

Assuming a normal distribution we find the standardized z scores for a:-

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b
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3 years ago

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2 years ago

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Anestetic [448]

Answer:

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Step-by-step explanation:

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Where,

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b = y-intercept, which is the initial value or the distance between the cities = 420

Plug in the values into the slope-intercept equation, to represent the distance y in miles remaining after driving x hours. You would have:

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2 years ago