What is the answer for y=mx+b
1 answer:
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Check the picture below.
so, if we add all the arcs provided, we have a total of 153° + 60° + 53°, which gives us 270°.
keeping in mind that a circle has a total of 360°, the shaded region has to be a sum of 360° - 270°, or 90°.
now, notice the tickmarks on those angles in the graph above, meaning those two angles are twins, and 90°/2 is 45°, so each of those twins is 45°.
arcYW = 60° + 45°.
so, if we add all the arcs provided, we have a total of 153° + 60° + 53°, which gives us 270°.
keeping in mind that a circle has a total of 360°, the shaded region has to be a sum of 360° - 270°, or 90°.
now, notice the tickmarks on those angles in the graph above, meaning those two angles are twins, and 90°/2 is 45°, so each of those twins is 45°.
arcYW = 60° + 45°.
Answer:
The correct option is;
C. 3. ∠BDE ≅∠BAC, Corresponding Angles Postulate 4. ∠B ≅ ∠B Reflexive Property of Equality
Step-by-step explanation:
The two column proof can be written as follows;
Statement, Reason
1. , Given
2. is a transversal , Conclusion from statement 1.
We note that ∠BDE and ∠BAC are on the same side of the transversal relative to the parallel lines, and are therefore, corresponding angles.
Therefore, we have;
3. ∠BDE ≅∠BAC, Corresponding Angles Postulate
Also
4. ∠B ≅ ∠B, Reflexive Property of Equality
In the two triangles, ΔABC and ΔDBE, we have ∠BDE ≅∠BAC and ∠B ≅ ∠B,
From ∠BDE + ∠B + ∠BED = 180°
∠BAC + ∠B + ∠BCA = 180°
Therefore, ∠BED = ∠BCA Substitution property of equality
Which gives;
5, ΔABC ~ ΔDBE, Angle Angle Similarity Postulate
6. BD/BA = BE/BC, Converse of the Side-Side-Side Similarity Theorem