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borishaifa [10]
3 years ago
7

At a concession stand five hotdogs and two hamburgers cost 8.00 two hotdogs and five hamburgers cost 9.50 find the cost of one h

ot dog and one hamburger
Mathematics
1 answer:
Svetach [21]3 years ago
6 0
Think of this situation as a system of equations.

let y be the price of hotdogs
let x be the price of hamburgers

5y + 2x = 8
2y + 5x = 9.50

now use your solution method of choice
substitution, elimination, matrices, etc
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-26 = -8x + 6
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The ratio between the number of red and green marbles in a box is 3:7. How many marbles are in the box if there are 20 fewer red
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A sign company charges $28 per yard for each custom made banner. Ms gill orders 2 banners that are each 17/8 yards long and 1 ba
vampirchik [111]
You start by writing your expression. Since each banner cost 28 per yard, you're going to multiply the price by the length by the number of banners she bought. (28)(17/8)(2)+(28)(25/8)=206.50
7 0
3 years ago
Find the fourth roots of i
antoniya [11.8K]

Answer:

  1∠22.5°, 1∠112.5°, 1∠202.5°, 1∠292.5°

Step-by-step explanation:

A root of a complex number can be found using Euler's identity.

<h3>Application</h3>

For some z = a·e^(ix), the n-th root is ...

  z = (a^(1/n))·e^(i(x/n))

Here, we have z = i, so a = 1 and z = π/2 +2kπ.

Using r∠θ notation, this is ...

  i = 1∠(90° +k·360°)

and

  i^(1/4) = (1^(1/4))∠((90° +k·360°)/4)

  i^(1/4) = 1∠(22.5° +k·90°)

For k = 0 to 3, we have ...

 for k = 0, first root = 1∠22.5°

  for k = 1, second root = 1∠112.5°

  for k = 2, third root = 1∠202.5°

  for k = 3, fourth root = 1∠292.5°

4 0
1 year ago
The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of itsâ height, and
storchak [24]

The question is incomplete.Here is the complete question.

The load that can be supported by a rectangular beam varies jointly as the width of the beam and the square of its length, and inversely as the length of the beam. A beam 13 feet long, with a width of 6 inches and a height of 4 inches can support a maximum load of 800 pounds. If a similar board has a width of 8 inches and a height of 7 inches, how long must it be to support 1300 pounds?

Answer: It must be 392 inches or approximately 33 feet.

Step-by-step explanation: According to the question, the measures (width, length and height) of a beam and the weight it supports are in a relation of <u>proportionality</u>, i.e., if divided, the result is a constant.

For the first load:

width = 6in

height = 4in

length = 13ft or 156in

weight = 800lbs

Then, constant will be:

\frac{6.4^{2}}{156} k = 800

k=\frac{800.156}{96}

k = 1300

For the similar beam:

\frac{8.7^{2}}{L}1300=1300

L = 49.8

L = 392in or 32.8ft

A similar board will support 1300lbs if it has 392 inches or 32.8 feet long.

6 0
3 years ago
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