Answer:
The ratio of the drag coefficients
is approximately 0.0002
Step-by-step explanation:
The given Reynolds number of the model = The Reynolds number of the prototype
The drag coefficient of the model,
= The drag coefficient of the prototype, 
The medium of the test for the model,
= The medium of the test for the prototype, 
The drag force is given as follows;

We have;

Therefore;







= (1/17)^3 ≈ 0.0002
The ratio of the drag coefficients
≈ 0.0002.
Answer: x=2−2√3,2+2√3
Step-by-step explanation:
Answer:
A. 7pi>21
Step-by-step explanation:
7*pi=21.99
21.99>21
X - 3 = 7
add 3 to both sides
x - 3 + 3 = 7 + 3
x = 10
addition property of equality