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Ganezh [65]
3 years ago
10

Provide a set of step by step instructions to make 750 mL of 1.5 M calcium chloride solution.

Chemistry
1 answer:
DiKsa [7]3 years ago
3 0

Answer: PLease see answer in explanation column

Explanation:

FIRST STEP

We  find the grams ( mass ) of solute required to prepare the solution by using  the formula

grams ( mass ) of solute, g(CaCl2)= Molar mass x Molarity of the solution x Volume of the solution

Therefore Preparing 750 mL of 1.5 M calcium chloride solution, we have that Molar mass of Calcium chloride =110.98 g/mol

g(CaCl2) =110.98 g/mol X 1.5mol/L X 0.75L

g(CaCl2) =124.8525g CaCl2

SECOND STEP

Now Dissolve 124.8525g CaCl2 in about 350ml of distilled water then add more water until the final volume be comes 750ml

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Read 2 more answers
You need to prepare 150 mL of 0.1 M solution of silver chloride. How much silver chloride is required?
Rudiy27

Answer:

amount of silver chloride required is 0.015 moles or 2.1504 g

Explanation:

0.1M AgCL means 0.1mol/dm³ or 0.1mol/L

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if 0.1mol of AgCl is contained in 1000mL of solution

then x will be contained in 150mL of solution

cross multiply to find x

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mass of AgCl = moles *molar mass

                       =0.015*143.36

                        =2.1504g

                        =

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