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Sonja [21]
3 years ago
11

In which pair do both compounds exhibit predominantly ionic bonding? A) KCl and CO2 B) SO2 and BaF2 C) F2 and N2O D) N2O3 and Rb

2O E) NaF and SrO
Chemistry
1 answer:
gtnhenbr [62]3 years ago
5 0

Answer:

E) NaF and SrO

Explanation:

The ionic bonding occurs between atoms with a great difference in electronegativity. This usually happens between a metal and a non-metal.

<em>In which pair do both compounds exhibit predominantly ionic bonding? </em>

A) KCl and CO₂. NO. C and O are non-metals and present covalent bonding.

B) SO₂ and BaF₂. NO. S and O are non-metals and present covalent bonding.

C) F₂ and N₂O. NO. Both compounds contain non-metals and present covalent bonding.

D) N₂O₃ and Rb₂O. NO. N and O are non-metals and present covalent bonding.

E) NaF and SrO. YES. Na and Sr are metals while F and O are non-metals.

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B) 1 and 3

it's the right answer

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How do H3O+ and OH relate to acids, bases and the pH scale?
Liula [17]

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Explanation:

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6 0
2 years ago
Which factor is generally responsible for high melting points?
vlabodo [156]

A. High intermolecular forces of attraction. If there are high intermolecular forces, the molecules will need large energies to escape into the liquid. The substance will nave a high melting point.

The other options are <em>incorrect </em>because they are <em>weak force</em>s. They would cause <em>low melting points</em>.

7 0
3 years ago
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Which substance can not be broken down by a
Tomtit [17]

Answer:  (3) silicon

Explanation:

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7 0
3 years ago
Silver bromide (AgBr) has a solubility of 7.07 × 10^-7 mol/L
kirill115 [55]

a. AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)

b.  Ksp AgBr = s²

c. 5 x 10⁻¹³  mol/L

<h3>Further explanation</h3>

Given

solubility AgBr = 7.07 x 10⁻⁷ mol/L

Required

The dissolution reaction

Ksp

The solubility product constant

Solution

a. dissolution reaction of AgBr

AgBr(s)⇒ Ag⁺(aq) + Br⁻(aq)

b. Ksp

Ksp AgBr  = [Ag⁺]  [Br⁻]

Ksp AgBr = (s) (s)

Ksp AgBr = s²

c. Ksp AgBr = (7.07 x 10⁻⁷)² = 5 x 10⁻¹³  mol/L

7 0
3 years ago
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