Answer: 0.082 atm L k^-1 mole^-1
Explanation:
Given that:
Volume of gas (V) = 62.0 L
Temperature of gas (T) = 100°C
Convert 100°C to Kelvin by adding 273
(100°C + 273 = 373K)
Pressure of gas (P) = 250 kPa
[Convert pressure in kilopascal to atmospheres
101.325 kPa = 1 atm
250 kPa = 250/101.325 = 2.467 atm]
Number of moles (n) = 5.00 moles
Gas constant (R) = ?
To get the gas constant, apply the formula for ideal gas equation
pV = nRT
2.467 atm x 62.0L = 5.00 moles x R x 373K
152.954 atm•L = 1865 K•mole x R
To get the value of R, divide both sides by 1865 K•mole
152.954 atm•L / 1865 K•mole = 1865 K•mole•R / 1865 K•mole
0.082 atm•L•K^-1•mole^-1 = R
Thus, the value of gas constant is 0.082 atm L k^-1 mole^-1
Hey there!
325 mL in liters:
325 / 1000 => 0.325 L
1 mole ( Ne ) ------------- 22.4 L ( at STP )
moles ( Ne ) ------------ 0.325 L
moles Ne = 0.325 * 1 / 22.4
moles Ne = 0.325 / 22.4
moles Ne = 0.0145 moles
hope this helps!
Explanation:
The ideal gas law or equation can also be reduced to the general gas law or the combined gas law.
Let us assume that n = 1;
From PV = nRT ideal gas law
= R (constant) if n = 1
Therefore, the combined gas law is;
The expression is a combination of Boyle's Law and Charles's law.
learn more:
Boyle's law brainly.com/question/8928288
#learnwithBrainly
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