We have that the original pressure of this gas is mathematically given as
P2=17.854 kPa
<h3>
Boyle's law</h3>
Question Parameters:
AT constant temperature, a gas is compressed from 5.5 L to 1 L.
At 1 L, the pressure of the gas is 98.2 kPa
Generally the equation for Boyle's law is mathematically given as
P1V1=P2V2
Therefore
P2=17.854 kPa
For more information on Pressure visit
brainly.com/question/25688500
Answer:
6 moles of oxygen
Explanation:We can find from the chemistry equation
C3H7SH(l)+6O2---3CO2(g)+SO2(g)+4H2O(g)
6 moles O2 ~4 moles H2O
Answer:
3 : 1
Explanation:
The following data were obtained from the question:
Initial temperature (T₁) = T
Initial pressure (P₁) = P
Final temperature (T₂) = 3T
Final pressure (P₂) =..?
Since the volume is constant, we shall use the following formula P₁ /T₁ = P₂ /T₂ to obtain the final pressure. This is illustrated below:
P₁ /T₁ = P₂ /T₂
P/T = P₂ /3T
Cross multiply
T × P₂ = P × 3T
Divide both side by T
P₂ = P × 3T /T
P₂ = P × 3
P₂ = 3P
Therefore, the final pressure is tripled.
Finally, we shall determine the ratio of the final pressure to the initial pressure as follow:
Initial pressure (P₁) = P
Final pressure (P₂) = 3P
Final pressure (P₂) : Initial pressure (P₁)
P₂ : P₁ => 3P/P
P₂ : P₁ => 3 : 1
Therefore, the ratio of the final pressure to the initial pressure is 3 : 1
Because they used to be alive
Answer: It shows how much atomic mass of calcium weights by its self. You round it so it says 40.08 it would just be 40.
Explanation:
