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2 years ago

HELP PLEASE with this question

Mathematics

1 answer:

grin007 [14]2 years ago

7 0

No it's not a function pretty sure

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Evaluate the triple integral_E x^6e^y dV where E is bounded by the parabolic cylinder z = 25 - y^2 and the planes z = 0, x = 5,

Nimfa-mama [501]

Nothing crazy here, just a matter of figuring out the limits of integration.

$\displaystyle\iiint_Ex^6e^y\,\mathrm dV=\int_{-5}^5\int_{-5}^5\int_0^{25-y^2}x^6e^y\,\mathrm dz\,\mathrm dy\,\mathrm dx$

$=\displaystyle\int_{-5}^{-5}\int_{-5}^5x^6e^y(25-y^2)\,\mathrm dy\,\mathrm dx$

$=\displaystyle\left(\int_{-5}^5x^6\,\mathrm dx\right)\left(\int_{-5}^5e^y(25-y^2)\,\mathrm dy\right)=\boxed{\frac{625,000(3+2e^{10})}{7e^5}}$

4 0

2 years ago

A fisherman uses a spring scale to weigh a tilapia fish. He records the fish weight as a kilograms and notices that the spring s

belka [17]

Answer:

k = $\frac{980a}{b}$

Step-by-step explanation:

Fisherman noticed a stretch in the spring = 'b' centimetres

Weight of the fish = a kilograms

If force applied on a spring scale makes a stretch in the spring then Hook's law for the force applied is,

F = kΔx

Where k = spring constant

Δx = stretch in the spring

F = weight applied

F = mg

Here 'm' = mass of the fish

g = gravitational constant

F = a(9.8)

= 9.8a

Δx = b centimetres = 0.01b meters

Therefore, 9.8a = k(0.01b)

k = $\frac{9.8a}{0.01b}$

k = $\frac{980a}{b}$

Therefore, spring constant of the spring will be determined by the expression, k = $\frac{980a}{b}$

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2 years ago

Find the circumference of the circle. PLEASE HELP I HAVE 5 MINUTES LEFT :(

Ipatiy [6.2K]

Answer:

18.84

Step-by-step explanation:

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3 years ago

If C = 1+ p2 + 3p and B = 2p + 6p, find an expression that equals 2C – – B in

drek231 [11]

Answer:

2p² + 14p + 2

Step-by-step explanation:

Given that;

C= 1+p²+3p

B=2p+6p

The expression that equals to : 2C - -B will be;

2{1+p²+3p} - {-2p-6p}

2+2p²+6p + 2p + 6p

2p² + 6p +2p +6p +2

2p² + 14p + 2

4 0

2 years ago

<img src="https://tex.z-dn.net/?f=4x%5E%7B0%7D%20x16x%5E%7B0%7D" id="TexFormula1" title="4x^{0} x16x^{0}" alt="4x^{0} x16x^{0}"

statuscvo [17]

Answer:

Step-by-step explanation:

its just how it is

8 0

2 years ago