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3 years ago

I need help on this question

Mathematics

1 answer:

solong [7]3 years ago

7 0

Answer:

Diego: y = 11 + 5 x

Emilia: y = 60 - 2 x

Step-by-step explanation:

y for saving and x for weeks

Diego: y = 11 + 5 x

Emilia: y = 60 - 2 x

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20 POINTS!!!! If eight is added to twice a number and the sum is multiplied by five result is the same as if the number is multi

Sauron [17]

<h3>The value of x is equal to -2.</h3>

5(2x + 8) = -8x + 4

Distributive property.

10x + 40 = -8x + 4

Add 8x to both sides.

18x + 40 = 4

Subtract 40 from both sides.

18x = -36

Divide both sides by 18

x = -2

6 0

3 years ago

What is KN + IK? !it’s not 1!

sergiy2304 [10]

The answer is 6, K-N is 4, and I-K is 2, and as we all know, 4+2=6

6 0

3 years ago

Mohamed decided to track the number of leaves on the tree in his backyard each year The first year there were 500 leaves Each ye

svetlana [45]

Answer:

The required recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

Step-by-step explanation:

Mohamed decided to track the number of leaves on the tree in his backyard each year.

The first year there were 500 leaves

$Year \: 1 = 500$

Each year thereafter the number of leaves was 40% more than the year before so that means

$Year \: 2 = 500(1+0.40) = 500\times 1.4\\$

For the third year the number of leaves increase 40% than the year before so that means

$Year \: 3 = 500\times 1.4(1+0.40) = 500 \times 1.4^{2}\\$

Similarly for fourth year,

$Year \: 4 = 500\times 1.4^{2}(1+0.40) = 500\times 1.4^{3}\\$

So we can clearly see the pattern here

Let f(n) be the number of leaves on the tree in Mohameds back yard in the nth year since he started tracking it then general recursive formula is

$f(n)= 500\times(1.4)^{n-1}\\$

This is the required recursive formula to find the number of leaves for the nth year.

Bonus:

Lets find out the number of leaves in the 10th year,

$f(10)= 500\times(1.4)^{10-1}\\\\f(10)= 500\times(1.4)^{9}\\\\f(10)= 500\times20.66\\\\f(10)= 10330$

So there will be 10330 leaves in the 10th year.

3 0

3 years ago

Read 2 more answers

Two parallel lines are cut by a transversal. Which statements are true for all such cases? Select three that apply.

Rudiy27

Answer:

Step-by-step explanation:

Each pair of vertically opposite angles are equal. If you mean vertical angles as in 90 degrees, you should qualify the question

Each pair of alternate interior angles is congruent (think it should be are congruent).

Each pair of corresponding angles is congruent

8 0

3 years ago

I need help with these three problems (college algebra)

Paraphin [41]

5. After 6 hours, the concentration is halved. After 12 hours, it will be quartered. If the original concentration is 200 nmol, a quarter is 50 nmol.

14. The population doubles after 3 hours, and a day is 24 hours. That means that the original population should be multiplied by $2^{24/3}$ , or $2^8$ . 3 million times $2^8$ is 3 * 256 million, or 768 million.

15. The concentration is halved every 8 hours and the original concentration is 100 nmol. So now, how many times do you halve 100 to get to 12.5?

100/2 = 50, 50/2 = 25, 25/2 = 12.5. That's three times. 3 * 8 is 24 hours, or 1 day.

8 0

3 years ago

Read 2 more answers