Answer:
I dunno
Step-by-step explanation:
You cant see the words lol
Using vector concepts, it is found that:
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
<h3>How can a vector be represented in component notation?</h3>
Given a magnitude M and angle
, then a vector V can be represented as follows in component notation:

In this problem, the magnitude and the angle are given, respectively, by:

Hence:
V = [12cos(143º), 12sin(143º)] = (-9.58, 7,22).
Which means a displacement of 9.58 miles to the west(negative x = west) and 7.22 miles to the north(positive y = north).
The component form is of approximately (-9.58, 7,22). It means that the ship is about 9.58 miles to the west and about 7.22 miles to the north of where the ship left the port.
More can be learned about vectors at brainly.com/question/24606590
#SPJ1
we know the segment QP is an angle bisector, namely it divides ∡SQR into two equal angles, thus ∡1 = ∡2, and ∡SQR = ∡1 + ∡2.
![\bf \begin{cases} \measuredangle SQR = \measuredangle 1 + \measuredangle 2\\\\ \measuredangle 2 = \measuredangle 1 = 5x-7 \end{cases}\qquad \qquad \stackrel{\measuredangle SQR}{7x+13} = (\stackrel{\measuredangle 1}{5x-7})+(\stackrel{\measuredangle 2}{5x-7}) \\\\\\ 7x+13 = 10x-14\implies 13=3x-14\implies 27=3x \\\\\\ \cfrac{27}{3}=x\implies 9=x \\\\[-0.35em] ~\dotfill\\\\ \measuredangle SQR = 7(9)+13\implies \measuredangle SQR = 76](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Bcases%7D%20%5Cmeasuredangle%20SQR%20%3D%20%5Cmeasuredangle%201%20%2B%20%5Cmeasuredangle%202%5C%5C%5C%5C%20%5Cmeasuredangle%202%20%3D%20%5Cmeasuredangle%201%20%3D%205x-7%20%5Cend%7Bcases%7D%5Cqquad%20%5Cqquad%20%5Cstackrel%7B%5Cmeasuredangle%20SQR%7D%7B7x%2B13%7D%20%3D%20%28%5Cstackrel%7B%5Cmeasuredangle%201%7D%7B5x-7%7D%29%2B%28%5Cstackrel%7B%5Cmeasuredangle%202%7D%7B5x-7%7D%29%20%5C%5C%5C%5C%5C%5C%207x%2B13%20%3D%2010x-14%5Cimplies%2013%3D3x-14%5Cimplies%2027%3D3x%20%5C%5C%5C%5C%5C%5C%20%5Ccfrac%7B27%7D%7B3%7D%3Dx%5Cimplies%209%3Dx%20%5C%5C%5C%5C%5B-0.35em%5D%20~%5Cdotfill%5C%5C%5C%5C%20%5Cmeasuredangle%20SQR%20%3D%207%289%29%2B13%5Cimplies%20%5Cmeasuredangle%20SQR%20%3D%2076)
The best thing to do here is to divide $4.85 by 10, and then multiply it by 2.5. $4.85/10= $0.48. $0.48x2.5= $1.20
Therefore,the discount is $1.20, you've then got to subtract this from $4.85. $4.85-$1.20= $3.65
$3.65 is the sale price of the pizza.
Hope this helps :)
Answer:
Step-by-step explanation:
2g + h = 2 --------------(I)
g - h = -5------------(II)
g = -5 + h
Plugin g = -5 + h in equation (I)
2(-5 + h) + h = 2 {Distributive property:a(b+c) = a*b +a*c}
(-5)*2 + h *2 + h= 2
-10 + 2h + h = 2
3h = 2 + 10
3h = 12
h = 12/3
h = 4
Substitute h= 6 in equation (I)
2g + 4 = 2
2g = 2 - 4
2g = -2
g = -2/2
g = -1