Answer:
Stabilizer with area = 14 cm².
Step-by-step explanation:
Area of the wing = 101.25 cm²
Rule of the thumb is that area of stabilizer must be about 1/6 to 1/8 of the area of wing. So, first we calculate 1/6 of the area of the wing and 1/8 of the area of the wing. Area of stabilizer must be in between these two numbers.
1/6 of the area of wing =
1/8 of the area of wing =
This means, the area of horizontal stabilizer must be in between 12.656 cm² and 16.875 cm². From the given options only one option lies in between these two numbers and that is 14 cm²
Therefore, area of a good stabilizer design from the given options would be 14 cm²
Answer:
120
Step-by-step explanation:
i just answer the question
Answer:
When the dimensions of the shape, such as radius, height, or length change, both surface area and volume also change. However, the volume of the object always changes more than the surface area for the same change in dimensions.
Answer:
If it's all five then just round to the bigger ten , hundred or thousand. like if it's five then rounded to the nearest ten would be 10 .if it's 55 rounded to the nearest hundred is 100. if the number is 555 rounded to the nearest thousand is one thousand. remember if it's five or more round it to the bigger ten, hundred or thousand. if it's 4 or smaller then round it to the smaller ten ,hundred or thousand.
I HOPE IT CAN HELP:)
Plug in -2 for x and evaluate.
<span>f(-2) = (-2)^4 + 3(-2)^3 - 6(-2)^2 + 3
f(-2) = 16 - 24 - 24 + 3
f(-2) = -29
-2 is not a zero of the polynomial.
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