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lana66690 [7]
3 years ago
8

Find the length of the arc.

Mathematics
2 answers:
Bezzdna [24]3 years ago
5 0

Answer:

18.84 ft

Step-by-step explanation:

¼×2×3.14×12 = 18.84 ft

Dmitriy789 [7]3 years ago
4 0

Step-by-step explanation:

assuming 90° is the central angle measure then the degree measure of the arc would be 90°

though the question asks for length

to do this create a ratio of the degree measurement of the arc divided by the total degree measure of a circle which would be

90/360

next think about circumference, it's the measure of the length around a circle. that would be relevant to what the question is asking so calculate it the formula is C=2*pi*r

calculate and the circumference is 24pi

next multiply the total circumference by the ratio for the section we want in this case 90/360

arc length = 24pi * 90/360 = 6pi

therefore the answer is 6pi or 18.84 substituting 3.14 for pi

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if you put $1650 into a saving account with a simple interest rate of 2.3%, how much interest would you accrue after 7 years
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3 years ago
How many seconds will light leaving Los Angeles take to reach the following locations (a) San Francisco (about 500km), (b) Londo
kondor19780726 [428]

Answer:

a) It takes 0.0017s for the light to reach San Francisco.

b) It takes 0.033s for the light to reach London.

c) It takes 1.334s for the light to reach Mars.

d) It takes 149.7s for the light to reach Venus.

Step-by-step explanation:

Here we can solve this problem by using this following formula:

s = \frac{d}{t}

In which s is the speed(in km/s), d is the distance(in km) and t is the time(in s).

The light speed is 299 792 458 m / s = 299,792.458 km/s, so s = 299,792.458

(a) San Francisco (about 500km)

Find t when d = 500. So

s = \frac{d}{t}

299,792.458 = \frac{500}{t}

299,792.458t = 500

t = \frac{500}{299,792.458}

t = 0.0017s

It takes 0.0017s for the light to reach San Francisco.

b) London(about 10,000km)

Find t when d = 10,000. So

s = \frac{d}{t}

299,792.458 = \frac{10,000}{t}

299,792.458t = 10,000

t = \frac{10,000}{299,792.458}

t = 0.033s

It takes 0.033s for the light to reach London.

(c) the Moon (400,000km)

Find t when d = 400,000. So

s = \frac{d}{t}

299,792.458 = \frac{400,000}{t}

299,792.458t = 400,000

t = \frac{400,000}{299,792.458}

t = 1.334s

It takes 1.334s for the light to reach Mars.

(d) Venus (0.3 A.U. from Earth at its closest approach).

Each A.U. has 149,59,7871 km.

So 0.3 A.U. = 0.3*(149,597,871) = 44,879,361.3. This means that d = 44,879,361.3. So:

s = \frac{d}{t}

299,792.458 = \frac{44,879,361.3}{t}

299,792.458t = 44,879,361.3

t = \frac{44,879,361.3}{299,792.458}

t = 149.7s

It takes 149.7s for the light to reach Venus.

3 0
3 years ago
I need help with with problem please thanks!
liraira [26]
40 is the correct answer. Hope this helps :)
5 0
3 years ago
A cylindrical swimming pool has a diameter of 16 feet and a height of 3 feet. How many gallons of water can the pool contain? Ro
Sever21 [200]

Answer:

<em>4,524 gallons</em>

Step-by-step explanation:

The volume of any cylinder is 

 π (radius)² (height) .

The pool's radius is 1/2 its diameter = 8 ft.  So its volume is

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= π · (64 ft²) · (3 ft)

= π · 192 ft³

= 603.2 ft³ .

(603 ft³) · (7.5 gal / 1 ft³) = 4,524 gallons

Hope this helps :D

8 0
3 years ago
Read 2 more answers
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