PLEASE HELP!!! I WILL GIVE BRAINLIEST!!! PLEASE ANSWER ALL THE QUESTIONS!!!

Find the missing end point if H is the midpoint of PS. P(2,5) and H (3,4) find S (endpoint)

RUDIKE [14]

Answer:

(4,3)

Step-by-step explanation:

To find the midpoint add the end points and divide by 2

P(2,5) S ( sx, sy) and the midpoint is and H (3,4)

X coordinate

( 2+ sx) /2 = 3

Multiply each side by 2

2+sx = 3*2

2+sx = 6

Subtract 2

sx = 4

Y coordinate

( 5+ sy) /2 = 4

Multiply each side by 2

5+sy = 4*2

5+sy = 8

Subtract 5

sy = 3

The end point is

(4,3)

8 0

3 years ago

Read 2 more answers

Lisa completed the table to describe the product of a mystery one - digit factor and factor and each numbers

deff fn [24]

Answer: part A is 0, 2, 4, 6, 8 and part B is Because the products all are even, the mystery factor must also be an even number. We have selected all of the even one-digit numbers.

Step-by-step explanation:

So, the number you need to find is between 0 and 9, because is a 1-digit number. For example, it cannot be 10 because 10 is a 2-digit number.

So, the number could be like 0,1,2,3...etc

In the table, the "X" in the left upper corner is the symbol for multiplication.

The "?" in the left lower corner represents the mystery number.

The table shows that the product of the mystery number and 1,2,3,4 and 5 is always an even number

For example, the product of the mystery number and 3 is even.

That means that our mystery must be even.

So, we know that the mystery number is between 0 and 9 and it must be even.

Therefore, the mystery number can be one of the following numbers:

0, 2, 4, 6, 8

8 0

3 years ago

Are these easyyyyyyyyyyyyyyyyyyyyyyyy

mixer [17]

Answer:

no

Step-by-step explanation:

no they are not they are hard

4 0

3 years ago

I really need help!If someone answers this,I will be happy to mark the brainest answer!EXTRA:you can answer the top question for

andreev551 [17]

9) They traveled 31.9 hours over the 3-day trip.

10.9 + 8.6 + 12.4 = 31.9

10) She does not have enough money. She has $12, but everything she wants to purchase would cost $12.39.

Large drink = 1.79

Turkey sandwich = 4.85

1.79 + 4.85 = 6.64

6.64 + 5.75 = 12.39

5 0

3 years ago

Assume that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true

IgorLugansk [536]

Answer:

(a) 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

Step-by-step explanation:

We are given that the helium porosity (in percentage) of coal samples taken from any particular seam is normally distributed with true standard deviation 0.75.

(a) Also, the average porosity for 20 specimens from the seam was 4.85.

Firstly, the pivotal quantity for 95% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.85

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 20

$\mu$ = true average porosity

Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 95% confidence interval for the true mean, $\mu$ is ;

P(-1.96 < N(0,1) < 1.96) = 0.95 {As the critical value of z at 2.5% level

of significance are -1.96 & 1.96}

P(-1.96 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 1.96) = 0.95

P( $-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

P( $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.95

95% confidence interval for $\mu$ = [ $\bar X-1.96 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+1.96 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.85-1.96 \times {\frac{0.75}{\sqrt{20} } }$ , $4.85+1.96 \times {\frac{0.75}{\sqrt{20} } }$ ]

= [4.52 , 5.18]

Therefore, 95% confidence interval for the true average porosity of a certain seam is [4.52 , 5.18].

(b) Now, there is another seam based on 16 specimens with a sample average porosity of 4.56.

The pivotal quantity for 98% confidence interval for the population mean is given by;

P.Q. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample average porosity = 4.56

$\sigma$ = population standard deviation = 0.75

n = sample of specimens = 16

$\mu$ = true average porosity

Here for constructing 98% confidence interval we have used One-sample z test statistics as we know about population standard deviation.

So, 98% confidence interval for the true mean, $\mu$ is ;

P(-2.3263 < N(0,1) < 2.3263) = 0.98 {As the critical value of z at 1% level

of significance are -2.3263 & 2.3263}

P(-2.3263 < $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ < 2.3263) = 0.98

P( $-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < ${\bar X-\mu}$ < $2.3263$ ) = 0.98

P( $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ < $\mu$ < $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ) = 0.98

98% confidence interval for $\mu$ = [ $\bar X-2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ , $\bar X+2.3263 \times {\frac{\sigma}{\sqrt{n} } }$ ]

= [ $4.56-2.3263 \times {\frac{0.75}{\sqrt{16} } }$ , $4.56+2.3263 \times {\frac{0.75}{\sqrt{16} } }$ ]

= [4.12 , 4.99]

Therefore, 98% confidence interval for the true average porosity of a another seam is [4.12 , 4.99].

7 0

3 years ago