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german
3 years ago
10

How to find a tangent ratio

Mathematics
1 answer:
maxonik [38]3 years ago
4 0

Answer:

The tangent ratio is the value received when the length of the side opposite of angle theta is divided by the length of the side adjacent to angle theta. It is very commonly abbreviated as tan.

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2. Draw the image of RST under the dilation with scale factor 2/3 and center of dilation (1,-1). Label the image RST .
professor190 [17]

Answer:

From the graph: we have the coordinates of RST i.e,

R = (2,1) , S = (2,-2) , T = (-1,-2)

Also, it is given the scale factor \frac{2}{3} and center of dilation C (1,-1)

The mapping rule for the center of dilation applied for the triangle as shown below:

(x, y) \rightarrow (\frac{2}{3}(x-1)+1, \frac{2}{3}(y+1)-1)

or

(x, y) \rightarrow (\frac{2}{3}x -\frac{2}{3}+1 , \frac{2}{3}y+\frac{2}{3}-1)

or

(x, y) \rightarrow (\frac{2}{3}x+\frac{1}{3} , \frac{2}{3}y-\frac{1}{3} )

Now,  

for R = (2,1)  

the image R' = (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(1)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{2}{3}-\frac{1}{3} )

⇒ R' = (\frac{5}{3} , \frac{1}{3})  

For S = (2, -2) ,

the image S'=  (\frac{2}{3}(2)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{4}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ S' = (\frac{5}{3} , -\frac{5}{3})

and For T = (-1, -2)

The image T' =  (\frac{2}{3}(-1)+\frac{1}{3} , \frac{2}{3}(-2)-\frac{1}{3} ) or

(\frac{-2}{3}+\frac{1}{3} , \frac{-4}{3}-\frac{1}{3} )

⇒ T' = (\frac{-1}{3} , \frac{-5}{3})

Now, label the image of RST on the graph as shown below in the attachment:

5 0
3 years ago
Can someone help me with 5-9 please?!?!? Thank you
valina [46]

5 is 1!!!!!!

Step-by-step explanation:

im sorry i dont know the others

3 0
2 years ago
What's the greatest common multiple of 84
VARVARA [1.3K]

in order to know the greatest common multiple of 84 you would have to compare it to another number

8 0
3 years ago
If each 6 in. On the scale drawing below equals 3 feet, what is the actual area of the shape in square units?
Liono4ka [1.6K]

Answer:

32 ft²

Step-by-step explanation:

Assuming the diagram attached below similar to the one required to complete the question below.

From the diagram,

Actaul Area of a parallelogram (A) = Actual Base(b)× actual heigth(h)

A = bh.......................... Equation 1

From the question,

If each 6 in on the scale drawing equals 3 feet

Given:

base on the scale drawing = 8 in.

Actual base(b) = (8×3)/6 = 4 feet.

Height on the scale drawing = 16 in

Actual height(h) = (16×3)/6 = 8 feet.

Substitute these values into equation 1

A = 4×8

A = 32 ft²

Hence the actual area of the shape is 32 ft²

4 0
3 years ago
Which choices are equivalent to the expression below?<br> Check all that apply.
Fittoniya [83]

Answer:

<em>A, D // other options are wrong.</em>

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3 years ago
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