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Ivan
3 years ago
9

The equation of a circle is given below.

Mathematics
1 answer:
alisha [4.7K]3 years ago
4 0

Coordinates of center and radius of circle is  (h,k)=(13.40,-2.60)\\r=10 .

<u>Step-by-step explanation:</u>

Here we have , The equation of a circle is given below.

(2 – 13.4)2 + (y + 2.6)2 = 100 or , (x -13.4)^2 + (y + 2.6)^2 = 100

We know that , Equation of circle is given by :

⇒ (x-h)^+(y-k)^2 =r^2  ...........(1)

where (h,k) are the coordinates of center of circle and r is the radius of circle . Let's simplify given equation of circle in question ;

⇒  (x -13.4)^2 + (y + 2.6)^2 = 100

⇒  (x -(13.4))^2 + (y - (-2.6))^2 = 100

⇒  (x -(13.4))^2 + (y - (-2.6))^2 = 10^2

Comparing this equation to (1) we get :

(h,k)=(13.40,-2.60)\\r=10

Therefore , Coordinates of center and radius of circle is (h,k)=(13.40,-2.60)\\r=10 .

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Find the center,vertices,foci,and asymptotes of the hyperbola.
bogdanovich [222]

Answer:

The center is (8 , -9)

The vertices are (11 , -9) and (5 , -9)

The foci are (8 , -9 + √58) and (8 , -9 - √58)

The equations of the asymptotes are y = 3/7(x − 8) - 9 , y = -3/7 (x − 8) - 9

Step-by-step explanation:

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the y-axis is

  (y - k)²/a² - (x - h)²/b² = 1

- The length of the transverse axis is 2 a  

- The coordinates of the vertices are ( h ± a , k )  

- The length of the conjugate axis is 2 b  

- The coordinates of the co-vertices are ( h , k ± b )

- The coordinates of the foci are (h , k ± c), where c² = a² + b²

- The equations of the asymptotes are y = ± a/b (x − h) + k

* Now lets solve the problem

∵ (y + 9)²/9 - (x - 8)²/49 = 1

∴ h = 8 and k = -9

∴ a² = 9 ⇒ a = ± 3

∴ b² = 49 ⇒ b = ± 7

∵ c² = a² + b²

∴ c² = 9 + 49 = 58

∴ c = ± √58

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∴ The center is (8 , -9)

∵ The coordinates of the vertices are ( h ± a , k )

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∴ The vertices are (11 , -9) and (5 , -9)

∵ The coordinates of the foci are (h , k ± c)

∴ The foci are (8 , -9 + √58) and (8 , -9 - √58)

∵ The equations of the asymptotes are y = ± a/b (x − h) + k

∴ The equations of the asymptotes are y  = 3/7 (x - 8) - 9 and  

   y  = -3/7 (x − 8) - 9

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