I need to find the range but I keep getting it wrong:(
1 answer:
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Hello!
As you can see, we have a radius of 6. If we divide, this means that this is 2.5 radians. To convert radians to degrees we use the formula below.
First of all we divide 180 by pi.
180/
≈57.3
Now we multiply by 2.5
57.3(2.5)=143.25°
Note that the angle we see is obtuse, or greater than 90°.
Therefore, ∠<span>θ</span>≈143.25°
Now we need to convert this back into radians. This can be represented by the equation below.
First we divide pi by 180 then multiply by our angle.
/180(143.25)≈2.5
Therefore, our angle theta is about 2.5 radians.
I hope this helps!
As you can see, we have a radius of 6. If we divide, this means that this is 2.5 radians. To convert radians to degrees we use the formula below.
First of all we divide 180 by pi.
180/
Now we multiply by 2.5
57.3(2.5)=143.25°
Note that the angle we see is obtuse, or greater than 90°.
Therefore, ∠<span>θ</span>≈143.25°
Now we need to convert this back into radians. This can be represented by the equation below.
First we divide pi by 180 then multiply by our angle.
Therefore, our angle theta is about 2.5 radians.
I hope this helps!
Answer: no, the confidence interval for the standard deviation σ cannot be expressed as 15.7 
4.7
There are three ways in which you can possibly express a confidence interval:
1) inequality
The two extremities of the interval will be each on one side of the "less then" symbol (the smallest on the left, the biggest on the right) and the symbol for the standard deviation (σ) will be in the middle:
11.0 < σ < 20.4
This is the first interval given in the question and it means <span>that the standard deviation can vary between 11.0 and 20.4
2) interval
</span>The two extremities will be inside a couple of round parenthesis, separated by a comma, always <span>the smallest on the left and the biggest on the right:
(11.0, 20.4)
This is the second interval given in the question.
3) point estimate </span><span> margin of error</span>
This is the most common way to write a confidence interval because it shows straightforwardly some important information.
However, this way can be used only for the confidence interval of the mean or of the popuation, not for he confidence interval of the variance or of the standard deviation.
This is due to the fact that in order to calculate the confidence interval of the standard variation (and similarly of the variance), you need to apply the formula:
which involves a χ² distribution, which is not a symmetric function. For this reason, the confidence interval we obtain is not symmetric around the point estimate and the third option cannot be used to express it.
There are three ways in which you can possibly express a confidence interval:
1) inequality
The two extremities of the interval will be each on one side of the "less then" symbol (the smallest on the left, the biggest on the right) and the symbol for the standard deviation (σ) will be in the middle:
11.0 < σ < 20.4
This is the first interval given in the question and it means <span>that the standard deviation can vary between 11.0 and 20.4
2) interval
</span>The two extremities will be inside a couple of round parenthesis, separated by a comma, always <span>the smallest on the left and the biggest on the right:
(11.0, 20.4)
This is the second interval given in the question.
3) point estimate </span><span>
This is the most common way to write a confidence interval because it shows straightforwardly some important information.
However, this way can be used only for the confidence interval of the mean or of the popuation, not for he confidence interval of the variance or of the standard deviation.
This is due to the fact that in order to calculate the confidence interval of the standard variation (and similarly of the variance), you need to apply the formula:
which involves a χ² distribution, which is not a symmetric function. For this reason, the confidence interval we obtain is not symmetric around the point estimate and the third option cannot be used to express it.