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Lorico [155]
2 years ago
9

A sound wave travels at 330m/s and has a wavelength of 2 m. calculate its frequency and period.

Mathematics
1 answer:
RoseWind [281]2 years ago
4 0

Answer:

frequency= 165Hz

period= \frac{1}{165}

Step-by-step explanation:

1. To calculate the frequency using the formula:

f = v/λ

where,

f=frequency (what the question asked)

v=speed of wave (given in the question=330m/s)

λ=wavelength (given in the question=2m)

SO,

f=\frac{330}{2}

= 165Hz

2. To calculate the period use the formula:

since f=\frac{1}{T}

therefore, T=\frac{1}{f}

where,

f= frequency (what we solved above=165Hz)

T= period (what the question asked)

SO,

T=\frac{1}{165}

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The proof is shown in the explanation below.

Step-by-step explanation:

Analysis:

The proof by induction focuses on n. In this case, let n = 1, and L^{1} will be a linear operator since L^{1} = L

The exercise will show that L^{n} is a linear operator on V and that L^{n+1} is also a linear operator on V. This, follows that:

L^{n+1} (av) = L(L^{m}(v_{1}+v_{2})\\                   = L(L^{m} (v_{1} + L^{m}v_{2})\\                   = L(L^{m}v_{1} + L(L^{m}v_{2})\\                   = L^{m+1}(v_{1}) + L^{m+1}(v_{2})

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2 years ago
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3 years ago
What is the solution to the equation 3 + 4 sqr root 4y = 4?
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Answer:

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Step-by-step explanation:

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3 years ago
Calculus question?
Ann [662]
Remark
If you don't start exactly the right way, you can get into all kinds of trouble. This is just one of those cases. I think the best way to start is to divide both terms by x^(1/2)

Step One
Divide both terms in the numerator by x^(1/2)
y= 6x^(1/2) + 3x^(5/2 - 1/2)
y =6x^(1/2) + 3x^(4/2)
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Step Two
Differentiate the y in the last step.
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y' = 3x^(-1/2) + 6x  I wonder if there's anything else you can do to this. If there is, I don't see it.

I suppose this is possible.
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Frankly I like the first answer better, but you have a choice of both.
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