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SSSSS [86.1K]
3 years ago
8

The length of each side of a square is increased by 2 inches. If the perimeter is 20 inches, write an equation to show the origi

nal length of the side
Mathematics
1 answer:
Archy [21]3 years ago
3 0
The new length side of the perimeter, we'll call p. The original length, we'll call o. P's equation looks like this:
p = 20 \times  \frac{1}{4}
Since 5 is the length of one side, subtract 2 from 5 to get 3. The equation looks like this:
o =  \frac{20}{4}  - 2
or simply
o = 5 - 2


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4) James Madison was born on March
gladu [14]

Answer:

166 years older.

Step-by-step explanation: Subtract 1751 from 1917

4 0
3 years ago
Simplify the expression. Assume that all variables represent nonzero real numbers.StartFraction (4 n Superscript 4 Baseline q Su
Alja [10]

Answer:

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

Step by step explanation:

\frac{ {(4 {n}^{4} {q}^{5})}^{2}  {(8 {n}^{4} q)}^{-2} }{  {(- 3 {nq}^{9})}^{ - 1}   {(4 {n}^{3} {q}^{9})  }^{3} }

first we will change the terms with negative superscrips to the other side of the fraction

\frac{{(4 {n}^{4} {q}^{5})}^{2}{(- 3 {nq}^{9})}^{ 1}}{{(4 {n}^{3} {q}^{9})}^{3} {(8 {n}^{4} q)}^{2} }

then we will distribute the superscripts

\frac{ {4}^{2} {n}^{2 \times 4} {q}^{2 \times 5} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{3 \times 3} {q}^{9 \times 3} {8 }^{2}{n}^{4 \times 2}  {q}^{2} }

\frac{ {4}^{2} {n}^{8} {q}^{10} (- 3) {nq}^{9}}{ {4 }^{3}{n}^{9} {q}^{27} {8 }^{2}{n}^{8}  {q}^{2} }

as when multiplying two powers that have the same base, we can add the exponents and, to divide podes with the same base, we can subtract the exponents

{4}^{2 - 3}  {q}^{10  + 9 - 2 - 27}  {n}^{8 + 1 - 8 - 9}  {8}^{ - 2}  { (- 3)}^{1}

{4}^{ - 1}  {q}^{ - 10}  {n}^{ - 8}  {8}^{ - 2}  { (- 3)}^{1}

then we will change again the terms with negative superscrips to the other side of the fraction

\frac{ - 3}{ 4 \times  {8}^{2}  {q}^{10} {n}^{8}  }

\frac{ - 3}{ 256  {q}^{10} {n}^{8}  }

4 0
3 years ago
A. 23 , 23/7, -41.80 , 56 , V34 , 106<br> b.-34, 34.05,-34.12,-45 ,-23, 8414<br> Greatest to least
Leto [7]

Answer

a. 106, 56, 23, 34, 23/7, -41.80

b. 8414, 34.05, -23, -34, -34.05, -34.12, -45

Step-by-step explanation:

i assume u meant 34 not V34

5 0
3 years ago
Read 2 more answers
I need help on this ASAP.
Sliva [168]

The seattle great wheel is an illustration of sectors, arcs, circumference and area of circles

<h3>The circumference of the wheel</h3>

The diameter is given as:

d = 175 feet

The circumference (C) is calculated as:

C = πd

This gives

C = 3.14 * 175

C = 549.5 feet

Hence, the circumference of the wheel is 549.5 feet

<h3>The area of the wheel</h3>

This is calculated as:

A = π(d/2)^2

This gives

A = 3.14 * (175/2)^2

A = 24040.625

Hence, the area of the wheel is 24040.625 square feet

<h3>The central angle (degrees)</h3>

This is calculated as:

θ = 360/n

Where n is the number of capsules

So, we have:

θ = 360/42

This gives

θ = 8.57 degrees

Hence, the central angle of the wheel in degrees is 8.57

<h3>The central angle (radians)</h3>

This is calculated as:

Radians = Degrees × π/180

So, we have:

θ = 360/42 * π/180

This gives

θ = π/21 rad

Hence, the central angle of the wheel in radians is π/21 rad

<h3>Arc length between two capsules</h3>

This is calculated as:

L = θ * d/2

So, we have:

L = π/21 * 175/2

This gives

L = 175π/42

Hence, the arc length between two capsules is 175π/42

<h3>Area of sector between two capsules</h3>

This is calculated as:

A = 0.5 * (d/2)^2 * θ

So, we have:

A = 0.5 * (175/2)^2 * π/21

This gives

A = 168π

Hence, the area of sector between two capsules is 168π

Read more about sector areas and arc lengths at:

brainly.com/question/4115882

8 0
2 years ago
Josh says that 2/3 is always the same as 4/6. Meghan says that 2/3 and 4/6 are equivalent fractions, but they could be different
Elodia [21]
Meghan is correct because you could have a giant chocolate bar then a tiny chocolate bar.


4 0
4 years ago
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