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torisob [31]
2 years ago
15

Kevin's bedroom is 14 feet long and

Mathematics
1 answer:
Arisa [49]2 years ago
8 0

Answer:

bathroom area is 1/4 area of bedroom

Step-by-step explanation:

bathroom area = 35 sq ft

bedroom area = 140 sq ft

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1. What is the solution to the system of equations graphed below? (1 point)
xenn [34]

Answer:

The answer is B

Step-by-step explanation:

lol i had the same question

5 0
2 years ago
Question Progress<br> Homework Progress<br> 4/<br> Work out the size of angle x.<br> 105<br> 140
agasfer [191]

Answer:

Step-by-step explanation:

Sum of angles of a triangle = 180

x + (180 - 105) + (180 -140) = 180

x + 75 + 40 = 180

x = 180 -75 - 40

x = 65

5 0
3 years ago
Sole the system by elimination -4x+9y=9 x-3y=-6
Natalka [10]

Answer:

A) -4x + 9y = 9

B) x -3y = -6

We multiply B) by 3

B) 3x -9y = -18 Then add it to A)

A) -4x + 9y = 9

-x = -9

x = 9

9 -3y = -6

3y = 15

y = 5


Step-by-step explanation:


5 0
2 years ago
A triangle's height is 10 feet more than its base. If the area of the triangle is 100 square feet, use factoring to find its dim
stiks02 [169]

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

Step-by-step explanation:

Height = base + 10

Area = 100 square ft

Area of a triangle= (1/2) (b) (h)

100 = (1/2) (b) (b + 10)

200 = b(b) + 10b

b(b) + 10b - 200 = 0

b(b) + 20b - 10b - 200 = 0

b ( b + 20) -10(b + 20) = 0

(b-10) (b+20) =0

b = 10 (or) b = -20

Here b is the length and cannot be negative.

So, b = 10ft

h = b + 10

h = 10 + 10

h = 20 ft.

The base length of the triangle is 10 ft. and the height of the triangle is 20ft.

6 0
3 years ago
Un chip tiene un espesor de 0,12 mm y un atomo de cobre mide 0,00000000133 m.¿cuantos atomos se necesita para alinearlos en el e
aleksandr82 [10.1K]

Answer:

El espesor de un chip es de 0.12mm

Y el diámetro de un átomo de cobre, mide aprox:

0.00000000133 m

Queremos saber cuantos átomos deberemos alinear de tal forma que la "cadena" de átomos de cobre mida 0.12mm

Eso es equivalente a ver cuantas veces entra 0.00000000133 m en 0.12mm

Primero, escribamos ambos valores en las mismas unidades, sabiendo que:

1m = 1000mm

Podemos reescribir:

0.00000000133m = 0.00000000133*(1000 mm) = 0.00000133mm

Entonces tenemos que ver cuantas veces entra 0.00000133mm en 0.12mm

Esto sera igual al cociente entre 0.12mm y  0.00000133mm, esto es:

N = (0.12mm)/(0.00000133mm) = 90,225.6

Redondeamos al próximo número entero:

N = 90,226

Esa es la cantidad de átomos que se necesitan.

7 0
3 years ago
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