All categories

3 years ago

Find the rational number whose decimal expansion is 0.3344444

1 answer:

6 0

Answer: The fraction 301/900
Note: I'm assuming the 4's continue on forever

==============================================

Work Shown:

I'm going to assume that the 4s go on forever. I'll represent this with three dots after the last 4 like so
0.334444...

Now let x = 0.334444...

Multiply both sides by 100
x = 0.334444...
100x = 100*(0.334444...)
100x = 33.444444...

And repeat with 1000
x = 0.334444...
1000x = 1000*(0.334444...)
1000x = 334.444444...

Then subtract and solve for x. Notice how the decimal parts line up and cancel
1000x-100x = (334.444444...) - (33.444444...)
1000x-100x = (334+0.444444...) - (33+0.444444...)
1000x-100x = 334+0.444444... - 33 - 0.444444...
1000x-100x = (334-33)+(0.444444... - 0.444444...)
900x = 334 - 33
900x = 301
x = 301/900

You might be interested in

The mean weight of the domesticated house cat is 9.2 pounds with a standard deviation of 3.4 pounds. If a cat has a z-score of -

ra1l [238]

Answer:

4.78 pounds

Step-by-step explanation:

We solve the above question using z score formula

z = (x-μ)/σ, where

x is the raw score

μ is the population mean = 9.2 pound

σ is the population standard deviation = 3.4 pounds

z = 1.3

We are to find x

Hence,

-1.3 = x - 9.2/3.4

Cross Multiply

-1.3 × 3.4 = x - 9.2

-4.42 = x - 9.2

x = -4.42 + 9.2

x = 4.78 pounds.

Therefore the weight of the cat is 4.78 pounds

5 0

3 years ago

Akira buys 10 tickets to a show. She also pays a $5 parking fee. If she spent $35 in total, how much did each ticket cost? Use x

Arte-miy333 [17]

Answer: Each ticket cost 3 dollars

Step-by-step explanation: First take 35 and subtract 5 which equals 30

then divide 30 by 10 and you get 3

7 0

3 years ago

1. x=1/(root3-root2). find rootx-(1/rootx) 2. if x=[root(a+2b)+root(a-2b)]/[root(a+2b)-root(a-2b]. show that bx^2-ax+b=0

timofeeve [1]

1. x = 1/ ( $\sqrt{3} - \sqrt{2)}$ = $\sqrt{3}+ \sqrt{2}$ ;
( $\sqrt{x} -1/ \sqrt{x} )^{2} = x + 1/x - 2 =$ =

6 0

3 years ago

Read 2 more answers

The combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 m

rewona [7]

Answer:

Approximately 50 pounds less carbon (in CO₂) will be produced by the second auto on this trip.

Step-by-step explanation:

We have been given that the combustion of one gallon of automobile fuel produces about 5 pounds of carbon (in CO₂). Two autos are making a trip of 600 miles.

Let us find amount of fuel used by autos by dividing the total distance by their mileage.

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\frac{\text{ 20 miles}}{\text{gallon}}}$

$\text{Fuel used by 1st auto}=\frac{\text{ 600 miles}}{\text{ 20 miles}}\times \text{gallon}$

$\text{Fuel used by 1st auto}=30 \text{ gallons}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\frac{\text{ 30 miles}}{\text{gallon}}}$

$\text{Fuel used by 2nd auto}=\frac{\text{ 600 miles}}{\text{ 30 miles}}\times \text{gallon}$

$\text{Fuel used by 2nd auto}=20 \text{ gallons}$

Let us find the difference of fuel used by both autos.

$\text{Number of gallons that 2nd auto used less than 1st auto}=30-20$

$\text{Number of gallons that 2nd auto used less than 1st auto}=10$

Since one gallon of automobile fuel produces about 5 pounds of carbon, so 10 gallons of fuel will produces $5\times 10=50$ pounds of carbon.

Since 2nd auto used 10 gallons less than 1st auto, therefore, 2nd auto will produce 50 pounds less carbon than 1st auto.

8 0

3 years ago

Given the following functions f(x) and g(x), solve (f + g)(3) and select the correct answer below:

kati45 [8]

(f+g)(3) = f(3) + g(3) = 6(3) + 3 + 3 -7 = 18 +6 -7 = 17.

Answer: 17

8 0

3 years ago

Read 2 more answers