$\bf 12~~,~~\stackrel{12+2}{14}~~,~~\stackrel{14+2}{16}~~,~~\stackrel{16+2}{18}\qquad \qquad \stackrel{\textit{common difference}}{d = 2} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} a_1=12\\ d = 2 \end{cases} \\\\\\ a_n=12+(n-1)2\implies a_n=12+2n-2\implies a_n=2n+10$

4 0

4 years ago

Help i have no idea how to do this i will mark you brainless if you actually try to get it right

blondinia [14]

Answer:

it is very simple, is you are given the co-ordinates for the graph plot them.

8 0

3 years ago

Tomas has a garden with a length of 2.4 meters and a width of 5/8 meters. Use benchmarks to estimate the area and perimeter of t

kumpel [21]

5/8 = .625 width

2 ( l + w ) = 2 ( 0.625+ 2.4) = 2 (3.025) = 6.05

Hop I become the brainiest

3 0

4 years ago