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Allisa [31]
4 years ago
7

Write an equation for the nth term of the arithmetic sequence 12,14,16,18

Mathematics
1 answer:
Elan Coil [88]4 years ago
4 0

\bf 12~~,~~\stackrel{12+2}{14}~~,~~\stackrel{14+2}{16}~~,~~\stackrel{16+2}{18}\qquad \qquad \stackrel{\textit{common difference}}{d = 2} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} a_1=12\\ d = 2 \end{cases} \\\\\\ a_n=12+(n-1)2\implies a_n=12+2n-2\implies a_n=2n+10

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Find the first four terms of the recursive sequence defined by the following formula: an = an-1 4 where a4 = 2 1 4 , , , 2 1 4.
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The first four-term of the sequence is found by the given equation a_{n-1} = 4a_n is given as 144, 36, 9, and 9/4.

<h3>What is a sequence?</h3>

A sequence is a list of elements that have been ordered in a sequential manner, such that members come either before or after.

The given equation will be

\rm a_n = \dfrac{a_{n-1}}{4} \\\\a_{n-1} = 4a_n

And

a_4 = 2 \dfrac{1}{4} = \dfrac{9}{4}

For n = 4, we have

\rm a_{4-1} = 4a_4\\\\a_3 \ \ \  = 4*\dfrac{9}{4} \\\\ a_3 \ \ \ = 9

For n = 3, we have

\rm a_{3-1} = 4a_3\\\\a_2 \ \ \  = 4*9 \\\\ a_2 \ \ \ = 36

For n = 2, we have

\rm a_{2-1} = 4a_2\\\\a_1 \ \ \  = 4*36 \\\\ a_1 \ \ \ = 144

More about the sequence link is given below.

brainly.com/question/21961097

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Step-by-step explanation:

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