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Allisa [31]
4 years ago
7

Write an equation for the nth term of the arithmetic sequence 12,14,16,18

Mathematics
1 answer:
Elan Coil [88]4 years ago
4 0

\bf 12~~,~~\stackrel{12+2}{14}~~,~~\stackrel{14+2}{16}~~,~~\stackrel{16+2}{18}\qquad \qquad \stackrel{\textit{common difference}}{d = 2} \\\\[-0.35em] ~\dotfill\\\\ n^{th}\textit{ term of an arithmetic sequence} \\\\ a_n=a_1+(n-1)d\qquad \begin{cases} a_n=n^{th}\ term\\ n=\textit{term position}\\ a_1=\textit{first term}\\ d=\textit{common difference}\\ \cline{1-1} a_1=12\\ d = 2 \end{cases} \\\\\\ a_n=12+(n-1)2\implies a_n=12+2n-2\implies a_n=2n+10

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f Daria repeats the experiment 50 more times, how many of those times should she expect to pull a yellow marble?
USPshnik [31]

Answer:

it matters how many colors are there

3 0
2 years ago
Taxi A charges a fee of $3.50, plus $1.75 per mile. Taxi B charges a few of $1.25, plus $2.00 per mile. At what distance would t
frez [133]
Taxi A
1mile £3.50+£1.75=£5.25
Taxi B
1mile £1.25+£2.00=£3.25

Taxi A
2miles £3.50+£3.50=£7.00
Taxi B
2miles £1.25+£4.00=£5.25

Taxi A
3miles £3.50+£5.25=£8.75
Taxi B
3miles £1.25+£6.00=£7.25

Taxi A
4miles £3.50+£7.00=£10.50
Taxi B
4miles £1.25+£8.00=£9.25

Taxi A
5miles £3.50+£8.75=£12.25
Taxi B
5miles £1.25+£10.00=£11.25

Taxi A
6miles £3.50+£10.50=£14.00
Taxi B
6miles £1.25+£12.00=£13.25

Taxi A
7miles £3.50+£12.25=£15.75
Taxi B
7miles £1.25+£14.00=£15.25

Taxi A
8miles £3.50+£14.00=£17.50
Taxi B
8miles £1.25+£16.00=£17.25

Taxi A
9miles £3.50+£15.75=£19.25 (the same)
Taxi B
9miles £1.25+£18.00=£19.25 (the same)

^^^
They would have to drive 9 miles for the taxi to cost the same.

Hope this helped, this is the longest way to work it out but also the simplest.
6 0
3 years ago
Roma sherry drove 80 miles from her home town to her​ parents' town. during her return​ trip, she was able to increase her speed
mr_godi [17]
<span>Answer: Roma Sherry drove 330 miles from her hometown to Tucson. During her return trip, she was able to increase her speed by 11 mph. If her return trip took 1 hour less time, find her original speed and her speed returning home. : Let s = original speed then (s+11) = return speed : Write a time equation: Time = distance%2Fspeed : Original time = return time + 1 hr 330%2Fs = 330%2F%28%28s%2B11%29%29 + 1 : Multiply equation by s(s+11) and you have: 330(s+11) = 330s + s(s+11) : 330s + 3630 = 330s + s^2 + 11s : 0 = 330s - 330s + s^2 + 11s - 3630 : A quadratic equation: s^2 + 11s - 3630 = 0 Factor this to: (s + 66)(s - 55) = 0 Positive solution s = 55 mph is original speed. : Find the time 330/55 = 6 hr, original time and 330/66 = 5 hrs, faster time; confirms our solution.</span>
7 0
3 years ago
Barbara earns $16.50 per hour for the first 8 hours she works What
Bingel [31]
In the morning she worked 3 hours and 45 minutes. In the afternoon she worked 5 hours and 15 minutes. That is a total of 9 hours. At $16.50 per hour for 8 hours that comes to $132. Plus the 1 hour over time with breaks down to $18.50 plus $8.25 totaling $24.75. Add that to the $132 and she made a total of $156.75 for Wednesday’s work. I hope this helps with your question.
8 0
3 years ago
Read 2 more answers
Right answer no lin or bot
kvv77 [185]

Answer:

2\frac{9}{10} or\frac{29}{10}

Step-by-step explanation:

Hope this helps! Have a great day ahead. Happy halloween :) Stay Safe <33

8 0
3 years ago
Read 2 more answers
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