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zzz [600]
3 years ago
10

Find the area of the triangular prism

Mathematics
1 answer:
Harrizon [31]3 years ago
4 0
94 meters is the correct answer i believe
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Hi I was a little confused on dilation can anyone help me (will mark Brainly)
Westkost [7]

Just divide the distance of each to point P by 2.

C would be 1 unit above and 2 units to the right of P.

D would be 1 unit below and 2 units to the right of P.

And so on...

Hope this helps

7 0
3 years ago
The area of a square is 22 square feet. Which is closest to the length of each side of the square?
Tju [1.3M]

Answer:

B, 3.7

Step-by-step explanation:

have a more thing square 2² solve is this

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3 years ago
What is Ed's mean speed if he bikes 37.8 miles in 2.7 hours? Round your answer to two decimal places, if necessary.
Vsevolod [243]

Answer:

v= 37.8 miles/ 2.7 hours = 14 miles/hrs

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3 0
3 years ago
To practice for a competition, Jasmine swam 930 meters in the pool each day for 4 weeks. How many kilometers did Jasmine swim in
aivan3 [116]

Answer:

To practice for a competition, Jasmine swam in those 4 weeks a total of 26.04\ km

Step-by-step explanation:

Hi

First of all, we need to determine how many days did Jasmine went to the pool in total, so if we have 1\ week=7\ Days, and if She has been going for 4 weeks, therefore 4\ weeks=28\ days.

Then we use Jasmine's rate of practice 930m/day.

So 930\frac{m}{day} (28\ days)=26,040m or 26.04\ km is the total distance swam by Jasmine in the four weeks.

8 0
4 years ago
I need a lot of help from the smartest people now right now
Dominik [7]

Answer:

K) I, II, and III

Step-by-step explanation:

Given the quadratic equation in standard form, <em>h </em>= -<em>at</em>² + <em>bt</em> + <em>c</em>, where <em>h </em>is the <u>height</u> or the projectile of a baseball that changes over time, <em>t</em>.  In the given quadratic equation, <em>c</em> represents the <u>constant term.</u> Altering the constant term, <em>c</em>, affects the <em>h</em>-intercept, the maximum value of <em>h</em><em>, </em>and the <em>t-</em>intercept of the quadratic equation.  

<h2>I. The <em>h</em>-intercept</h2>

The h-intercept is the value of the height<em>, h</em>, when <em>t = </em>0. This means that setting <em>t</em> = 0 will leave you with the value of the constant term. In other words:

Set <em>t</em> = 0:

<em>h </em>= -<em>at</em>² + <em>bt</em> + <em>c</em>

<em>h </em>= -<em>a</em>(0)² + <em>b</em>(0) + <em>c</em>

<em>h</em> = -a(0) + 0 + <em>c</em>

<em>h</em> = 0 + <em>c</em>

<em>h = c</em>

Therefore, the value of the h-intercept is the value of c.

Hence, altering the value of<em> c </em>will also change the value of the h-intercept.

<h2>II. The maximum value of <em>h</em></h2>

The <u>maximum value</u> of <em>h</em> occurs at the <u>vertex</u>, (<em>t, h </em>). Changing the value of <em>c</em> affects the equation, especially the maximum value of <em>h. </em>To find the value of the <em>t</em>-coordinate of the vertex, use the following formula:

<em>t</em> = -b/2a

The value of the t-coordinate will then be substituted into the equation to find its corresponding <em>h-</em>coordinate. Thus, changing the value of <em>c</em> affects  the corresponding <em>h</em>-coordinate of the vertex because you'll have to add the constant term into the rest of the terms within the equation. Therefore, altering the value of <em>c</em> affects the maximum value of <em>h.</em><em> </em>

<h2>III. The <em>t-</em>intercept</h2>

The <u><em>t-</em></u><u>intercept</u> is the point on the graph where it crosses the t-axis, and is also the value of <em>t</em> when <em>h</em> = 0. The t-intercept is the zero or the solution to the given equation. To find the <em>t</em>-intercept, set <em>h</em> = 0, and solve for the value of <em>t</em>.  Solving for the value of <em>t</em> includes the addition of the constant term, <em>c</em>, with the rest of the terms in the equation.  Therefore, altering the value of <em>c</em> also affects the<em> </em><em>t-intercept</em>.

Therefore, the correct answer is <u>Option K</u>: I, II, and III.

5 0
2 years ago
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