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alexdok [17]
3 years ago
6

How many formula units of CaO are in 32.7 g of CaO?

Chemistry
1 answer:
zhuklara [117]3 years ago
7 0

Answer:

D) 3.51x10²³ formula units

Explanation:

To know this, we need to calculate the molecular mass of CaO. To do that, let's use the atomic mass of each element of this compound.

Ca: 40.08 g/mol;    O: 16 g/mol

With these given AM, let's calculate the molar mass of CaO:

Mm CaO = 40.08 + 16 = 56.08 g/mol

Now that we have the MM of CaO, it's time to determine the moles of CaO:

moles = mass / MM

moles = 32.7 / 56.08 = 0.5831 moles

Finally to get the formula units, we need to use the Avogadro's number which is 6.02x10²³. According to this number, 1 mole of any substance has this number of atoms, molecules or formula units. So, if we have 0.5831 moles, then the formula units will be:

FU = 0.5831 * 6.02x10²³

<h2>FU = 3.51x10²³ formula units</h2>

Hope this helps

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8 0
4 years ago
When a solute dissolves, the process is referred to as _____.
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How many molecules of carbon dioxide are in 388.1 moles
crimeas [40]

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23

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3 years ago
To what volume (in mL) would you need to dilute 25.0mL of a 1.45 m solution of Kcl to make a 0.0245m solution of KCl
dezoksy [38]

Answer:

The answer is

<h2>1479.60 mL</h2>

Explanation:

In order to calculate the volume needed we use the formula

V_2 =  \frac{C_1V_1}{C_2}

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the diluted solution

V2 is the volume of thevdiluted solution

From the question

C1 = 1.45 M

V1 = 25 mL

C2 = 0.0245 M

So we have

V_2 =  \frac{1.45 \times 25}{0.0245}   =  \frac{36.25}{0.0245}  \\  = 1479.59...

We have the final answer as

<h3>1479.60 mL</h3>

Hope this helps you

4 0
3 years ago
The mass % of C in methane CH4 is a) 74.87 b) 7.743 c) 133.6 d) 25.13 €) 92.26 159
Iteru [2.4K]

Answer:

a) 74.87 % carbon

Explanation:

Molecular mass of CH₄ is 16.042 g / mole.

Now we divide the following reasoning for 1 mole of methane:

if in        16.042 g of CH₄ there are 12.01 g of carbon

then in  100 g of CH₄ there are X g of carbon

X = (100 × 12.01) / 16.042= 74.87 % carbon

8 0
3 years ago
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