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Vikentia [17]
3 years ago
7

The mass % of C in methane CH4 is a) 74.87 b) 7.743 c) 133.6 d) 25.13 €) 92.26 159

Chemistry
1 answer:
Iteru [2.4K]3 years ago
8 0

Answer:

a) 74.87 % carbon

Explanation:

Molecular mass of CH₄ is 16.042 g / mole.

Now we divide the following reasoning for 1 mole of methane:

if in        16.042 g of CH₄ there are 12.01 g of carbon

then in  100 g of CH₄ there are X g of carbon

X = (100 × 12.01) / 16.042= 74.87 % carbon

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Calculate the total quantity of heat required to convert 25.0 g of liquid ccl4(l from 35.0°c to gaseous ccl4 at 76.8°c (the norm
GREYUIT [131]

The solution would be like this for this specific problem:

<span>25.0 g CCl4 x (1 mole CCl4 / 153.8 g CCl4) = 0.163 moles CCl4 

 </span>(29.82 kJ / mole)(0.163 moles) = 4.86 kJ 

total heat = 1.11 kJ + 4.86 kJ = 5.97 kJ 

<span>I hope this helps and if you have any further questions, please don’t hesitate to ask again. </span>

6 0
4 years ago
A mixture containing initially 3.90 mole of NO(g) and 0.88 mole of CO2(g) was allowed to react in a flask of volume 1.00 L at a
Ymorist [56]

Answer:

Equilibrium constant Kc for the reaction will be 1.722

Explanation:

O2(g)+NO(g)→CO(g)+ NO2(g)

0.88    3.9        ---         ---

0.88x   3.9-x     x           x

GIVEN:

0.88X-X= 0.11

⇒ X=0.77

CO2(g)+NO(g) → CO(g) + NO2(g)

0.88       3.9         ---          ---

0.88-x    3.9-x      x            x

=              3.13       0.77      0.77

=0.11

Kc = \frac{[CO] *[NO2]} {[CO2]*[NO]}

     ={{0.77}×0.77÷{{0.11×3.13}}

     = 1.722

6 0
4 years ago
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stich3 [128]
The answer is 4 million, there are about 9-10 million unique organic compounds that are known to exist
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3 years ago
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aniked [119]

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3 years ago
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erastova [34]

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5 0
3 years ago
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