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2 years ago

Solving systems of equations using substitution with both equations in y=mx+b

Mathematics

1 answer:

UNO [17]2 years ago

5 0

1. solution: (x,y)=(1,12)
x + 11 = 12x
x = 1
x = 12 x 1
y = 12
(x,y) = (1,12)
if you need the rest, let me know.

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Mrs. Wigen conducted a survey in her math class. She asked each of her students to tell her how many pets they have at home. The

Lera25 [3.4K]

Answer:

4 : 25 to round off we have to see that

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4 : 25 to round off we have to see that If in ones place it is more than 5 or not if yes we will add to 1 no to tenths place

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3 years ago

Divide. Give the quotient and remainder.

Pavel [41]

Answer:

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Step-by-step explanation:

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3 years ago

What does |-|-40 equal to??

EleoNora [17]

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3 years ago

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A certain financial services company uses surveys of adults age 18 and older to determine if personal financial fitness is chang

zysi [14]

Answer:

The calculated z = 2.85 falls in the critical region z > 1.96 so we accept the null hypothesis that there is no difference between the population proportions for the two years.

Step-by-step explanation:

Let p1 be the sample of 1000 adults chosen in 2012 and

p2 be the sample of 1100 adults chosen in 2010

Part a:

The hypothesis that can be used to test for a significant difference between the population proportions for the two years is:

H0: p1-p2= 0 against the claim Ha: p1-p2≠0

Part b:

The sample proportion indicating that their financial security was more that fair in 2012 is

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In 2010 is:

p2^= 385/1100= 0.35

Part c:

p^c= 410+385/1000+1100= 0.3785

q^c= 1-p^c= 1-0.3785= 0.6124

The critical region is z > ±1.96

The test statistic is

z= p1^- p2^ / sqrt ( p^cq^c( 1/n1+ 1/n2)

z= 0.41-0.35 /sqrt( 0.3785*0.6124(1/1000 +1/1100)

z= 0.06 / 0.021036

z= 2.85

Conclusion

The calculated z = 2.85 falls in the critical region z > 1.96 so we accept the null hypothesis that there is no difference between the population proportions for the two years.

P- value : 0.00466

The result is significant( accept the null hypothesis) for value less than 0.05

Part d:

2012 2010

Sample 1000 1100

Proportions 0.41 0.35

Standard Error √0.41( 0.59)/1000 √0.35( 0.65)/1100

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The 95 % confidence interval estimate is (-0.018644, 0.10135

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3 years ago

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3 years ago

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