Answer:
In geometry, you can use deductive rules to prove that a given statement or conjecture is true or false using deductive reasoning.
Step-by-step explanation:
Answer:
a) 30 kangaroos in 2030
b) decreasing 8% per year
c) large t results in fractional kangaroos: P(100) ≈ 1/55 kangaroo
Step-by-step explanation:
We assume your equation is supposed to be ...
P(t) = 76(0.92^t)
__
a) P(10) = 76(0.92^10) = 76(0.4344) = 30.01 ≈ 30
In the year 2030, the population of kangaroos in the province is modeled to be 30.
__
b) The population is decreasing. The base 0.92 of the exponent t is the cause. The population is changing by 0.92 -1 = -0.08 = -8% each year.
The population is decreasing by 8% each year.
__
c) The model loses its value once the population drops below 1/2 kangaroo. For large values of t, it predicts only fractional kangaroos, hence is not realistic.
P(100) = 75(0.92^100) = 76(0.0002392)
P(100) ≈ 0.0182, about 1/55th of a kangaroo
Answer:
-7 and -1
Step-by-step explanation:
-7x-1=7
-7-1=-6
Answer:
18
Step-by-step explanation:
volume= r × h = 2 × 9= 18
We have been given two inequalities 
and 
. We are asked to find the integers that satisfy both inequalities.
Let us solve for our 1st inequality.
Upon combining our both inequalities, we will get:
This means that solution of our inequalities is x values greater than 
and less than 
.
We know that integers between and are: 
.
Therefore, our solution would be 
.
