2 years ago

What is the solution to the inequality below? −8≥40

Mathematics

1 answer:

Dominik [7]2 years ago

5 0

This solution is false. Hope this helped out

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3 years ago

If z^2+1/z^2=11 , find the value of z^3-1/z^3,using only the positive value of z-1/z

vredina [299]

Hello,

Let's assume

$t=z- \dfrac{1}{z} \\\\

t^2=z^2-2+ \dfrac{1}{z^2}= 11-2=9==\ \textgreater \ t=3\\\\

t^3=z^3-3z^2* \dfrac{1}{z} +3z* \dfrac{1}{z^2} - \dfrac{1}{z^3} \\\\
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$

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3 years ago

Can someone help me out with this ? 8(1 - 8p) + 8p

goldfiish [28.3K]

8(1-8p) + 8p
8 - 64p + 8p
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2 years ago

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inysia [295]

$\text{L.H.S}\\\\=\dfrac{\sin^4 A - \cos^4 A}{ \sin A + \cos A}\\\\\\=\dfrac{(\sin^2 A)^2-(\cos^2 A)^2}{\sin A + \cos A}\\\\\\=\dfrac{(\sin^2 A + \cos^2 A)(\sin^2 A-\cos^2 A)}{\sin A + \cos A}\\\\\\=\dfrac{1\cdot(\sin A+\cos A)(\sin A - \cos A)}{\sin A +\cos A}\\\\\\=\sin A - \cos A\\\\\\=\text{R.H.S}~~~ \\\\\text{Proved.}$

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2 years ago

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